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3 years ago

Need help with Algerbra math

Mathematics

1 answer:

makkiz [27]3 years ago

4 0

Answer:

57.5

Step-by-step explanation:

divide 92 by 1.6. I hope this helps

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timur paid $4.50 to enter the fair. he then bought a pretzel for $1.50 and played a game $1. last he rode a roller coaster for $

Soloha48 [4]

X-(4.5+1.5+1+3)= 8
x-10=8
+10. +10
x= 18

He took $18 to the fair. You take his original amount and subtract the things he paid for/bought to get what he came home with. I hope it helps!

8 0

2 years ago

Which statement describes a car lease?

Margaret [11]

Answer: Option C

Step-by-step explanation:

You get to use a car for a specific time period by making monthly payments

usually when you get a car lease you pick out the car and (as an example) lets say you have a 3 year lease, you will pay monthly payments for 3 years then return the car.

6 0

3 years ago

Read 2 more answers

Triana buys new furniture for $4200 and puts it on her credit card.She will pay 18% interest for 18 months and must make monthly

DerKrebs [107]

Answer:

$623.64

Step-by-step explanation:

To determine the money she could have saved if she paid the furniture in full, you have to determine the total amount she will pay when she completes the 18 payments and subtract the price of the furniture from that:

Total amount= 267.98*18

Total amount=4,823.64

$4,823.64-$4,200= $623.64

She have saved $623.64 if she paid for the furniture in full.

5 0

3 years ago

A student wanted to construct a 95% confidence interval for the mean age of students in her statistics class. She randomly selec

VMariaS [17]

Answer:

$19.1-3.355\frac{1.5}{\sqrt{9}}=17.42$

$19.1+3.355\frac{1.5}{\sqrt{9}}=20.78$

And the best option would be:

C. [17.42,20.78]

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=19.1$ represent the sample mean

$\mu$ population mean (variable of interest)

s=1.5 represent the sample standard deviation

n=9 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=9-1=8$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,8)".And we see that $t_{\alpha/2}=$

Now we have everything in order to replace into formula (1):

$19.1-3.355\frac{1.5}{\sqrt{9}}=17.42$

$19.1+3.355\frac{1.5}{\sqrt{9}}=20.78$

And the best option would be:

C. [17.42,20.78]

5 0

3 years ago

Drag a statement or reason to each box to complete this proof.

kotykmax [81]

Step-by-step explanation:

distribute the -2 to (x+1) you end up with -2x-2=8 (multiplication property). Add 2 to both sides to get rid of the -2 of the left (addition property). 8+2=10. -2x=10 divide the -2 to both sides. x=-5 (division property).

7 0

4 years ago

Read 2 more answers

Need help with Algerbra math​

Need help with Algerbra math