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Citrus2011 [14]

3 years ago

9

A construction job for gallery 10 painters were tasked with painting the interior these painters made up 40% of the painting cre

w so how many painters in all worked on this job

1 answer:

Harrizon [31]3 years ago

3 0

Answer:

Total number of painters = 25 painters

Step-by-step explanation:

Interior painting = 10 painters

These painters made up 40% of the painting crew

how many painters in all worked on this job?

Let

Total number of painters = x

Interior painters = 40% of x

10 = 40% * x

10 = 0.4 * x

10 = 0.4x

x = 10/0.4

x = 25 painters

Total number of painters = x = 25 painters

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Suppose you had D dollars in your bank account. you spent $22 but have at least $28 left. how much money did you have initially?

nalin [4]

Answer:

Answer:

d--22→ 28

d→ 50

Step-by-step explanation:

Let d dollars be the initial amount in your bank account.

We have been given that you spent $22, so the amount left after spending $22 will be: .

We are also told that after spending $22, you have at least $28. This means that the amount left after spending $22 will be greater than or equal to $28.

We can represent this information in an equation as:

Therefore, the inequality represents the initial amount of money you had.

Now let us solve for d by adding 22 to both sides of our inequality.

Therefore, initially you had at least $50.

Still stuck? Get 1-on-1 help from an expert tutor now.

Step-by-step explanation:

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8 0

2 years ago

For the given term, find the binomial raised to the power, whose expansion it came from: 15(5)^2 (-1/2 x) ^4

Elina [12.6K]

Answer:

<em>C.</em> $(5-\frac{1}{2})^6$

Step-by-step explanation:

Given

$15(5)^2(-\frac{1}{2})^4$

Required

Determine which binomial expansion it came from

The first step is to add the powers of he expression in brackets;

$Sum = 2 + 4$

$Sum = 6$

Each term of a binomial expansion are always of the form:

$(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......$

Where n = the sum above

$n = 6$

Compare $15(5)^2(-\frac{1}{2})^4$ to the above general form of binomial expansion

$(a+b)^n = ......+15(5)^2(-\frac{1}{2})^4+.......$

Substitute 6 for n

$(a+b)^6 = ......+15(5)^2(-\frac{1}{2})^4+.......$

[Next is to solve for a and b]

<em>From the above expression, the power of (5) is 2</em>

<em>Express 2 as 6 - 4</em>

$(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......$

By direct comparison of

$(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......$

and

$(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......$

We have;

$^nC_ra^{n-r}b^r= 15(5)^{6-4}(-\frac{1}{2})^4$

Further comparison gives

$^nC_r = 15$

$a^{n-r} =(5)^{6-4}$

$b^r= (-\frac{1}{2})^4$

[Solving for a]

By direct comparison of $a^{n-r} =(5)^{6-4}$

$a = 5$

$n = 6$

$r = 4$

[Solving for b]

By direct comparison of $b^r= (-\frac{1}{2})^4$

$r = 4$

$b = \frac{-1}{2}$

Substitute values for a, b, n and r in

$(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......$

$(5+\frac{-1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......$

Solve for $^6C_4$

$(5-\frac{1}{2})^6 = ......+ \frac{6!}{(6-4)!4!)}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{6!}{2!!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{6*5*4!}{2*1*!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{6*5}{2*1}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{30}{2}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15(5)^2(\frac{-1}{2})^4+.......$

<em>Check the list of options for the expression on the left hand side</em>

<em>The correct answer is </em> $(5-\frac{1}{2})^6$ <em />

3 0

3 years ago

Nathaniel builds birds and birdhouses using Lego blocks. Let BBB represent the number of birds and HHH represent the number of b

vladimir1956 [14]

Answer:

(C) Nathaniel can build at most 3 birdhouses.

Step-by-step explanation:

Given that:

$43B+215H \leq 3000$

where:

B represents the number of birds
H represents the number of Birdhouses

Nathaniel wants to build 50 birds(B) using lego Blocks, we want to determine how many birdhouses(H) he can build with the remaining Lego blocks.

If B=50

$43(50)+215H \leq 3000\\2150+215H \leq 3000\\\text{Subtract 2150 from both sides}\\215H \leq 3000-2150\\215H \leq 850\\\text{Divide both sides by 215}\\H \leq 3.95$

Therefore, Nathaniel can build at most 3 Birdhouses.

8 0

4 years ago

PLEASE HELP ILL GIVE BRAINLIEST

ella [17]

Answer:

1. The red one

2. 60%

3. 18,57%

Step-by-step explanation:

I use the way to calculate the percentage in question 2 and 3

2. (6:10)x100%

3. (13:7)x100%

6 0

3 years ago

Find the interquartile range for the data {5, 7, 9, 5, 6, 6, 6, 11, 11, 3, 3}

RoseWind [281]

Answer:

4

Step-by-step explanation:

i dont really know how to explain i used an algebra calculator

4 0

3 years ago