A 31 cm core sample from a large tree is to be divided into five pieces. Two of the pieces will be one length, and the other thr
1 answer:
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Answer:
Median highland = 16 mm
Median lowland = 16 mm
Step-by-step explanation:
For the highland area :
The sample size, n = 44
Obtain the median value using :
1/2 * (n + 1)th term
1/2 * (44 +1) th term
1/2 * 45 = 22.5th term.
(22nd + 23rd) term / 2
(16 + 16) / 2 = 16 mm
For the lowland area :
1/2 * (n + 1)th term
1/2 * (44 +1) th term
1/2 * 45 = 22.5th term.
(22nd + 23rd) term / 2
(12 + 12) / 2 = 12 mm
Answer:
Step-by-step explanation:
Let be , which can be simplified solely by algebraic means. We proceed to describe all the steps needed for simplification:
1) Given.
2) Distributive and associative properties.
3)
/Result
Answer:
By AA
ΔWXY ~ΔWVZ
Step-by-step explanation:
Here WXY is an isosceles triangle with legs WX & WY
So WX = WY
Hence ∠X = ∠Y
So ∠2= ∠3.
Now by angle sum property
∠1 + ∠2+∠3 = 180°
∠1+∠2+∠2=180°
2∠2 = 180° - ∠1 .......(1)
In triangle WVZ
WV = WZ
So ∠V = ∠Z
∠4 = ∠5
Once again by angle sum property
∠1 + ∠4 + ∠5=180°
∠1 + ∠4 + ∠4 = 180°
2∠4 = 180° - ∠1 ...(2)
From (1) & (2)
2∠2 = 2∠4
∠2=∠4
Now ∠W is common to both triangles
Hence by AA
ΔWXY ~ΔWVZ
Step-by-step explanation:
Let the required number be n
NOTE: A number is always 100% in itself.