9514 1404 393
Answer:
C. Midsegment of a Triangle Theorem
Step-by-step explanation:
After you eliminate the nonsense choices, the answer remains.
A - concurrency of medians requires 2 or more medians. There are no medians in this problem
B - there is no indication the triangle is isosceles
C - the applicable choice (segment DE is a "midsegment", hence parallel to BC)
D - has to do with measures of sides, which are not involved in this problem
Answer:
- (4, 0) and (-2, 0)
- (1, -9)
- (0, -8)
Step-by-step explanation:
Finding the x-intercepts :
- y-value of the x-intercept is 0
- 0 = (x - 4)(x + 2)
- x - 4 = 0 ⇒ x = 4
- x + 2 = 0 ⇒ x = -2
- The x-intercepts are : (4, 0) and (-2, 0)
Finding the vertex :
- Expanding the function f
- f(x) = (x - 4)(x + 2)
- f(x) = x² - 4x + 2x - 8
- f(x) = x² - 2x - 8
- Vertex = (h, k)
- h = -b/2a = -(-2)/2(1) = 1
- k = (1)² - 2(1) - 8
- k = 1 - 2 - 8 = -9
- The vertex is : (1, -9)
Finding the y-intercept :
- Substitute x = 0 in the function
- f(0) = 0² - 2(0) - 8
- f(0) = -8
- The y-intercept is : (0, -8)
Plug in n = 5 to find the 5th term
T(5) = 2(5) - 7
T(5) = 10 - 7
T(5) = 3
The 5th term is 3.
Area of wall = l×b
Length = 5m
Breadth = 20m
Area = 5×20
=100m²
Area of flex = side×side
= 2×2
= 4m²
Now no of flex that can be fitted = 100/4
= 25 flex
Must click thanks and mark brainliest
Answer:
Its is C.i and iii only
Step-by-step explanation:
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