The LCD is 12. Thus, your
(x-2)/4 - (x+3)/3 = -2 becomes 12((x-2)/4 - (x+3)/3 = -2), or
3(x-2) - 4(x+3) = -36
Then 3x - 6 - 4x - 12 = -36. Combining like terms,
-x = -36 + 18, or -x = -18, or x = 18.
Check this result by subbing 18 for x in the given equation.
Please note: You must use parentheses here as indicated to eliminate any ambiguity about order of operations and what divides into what.
To calculate the value of the half life we proceed as follows;
a/2=ae^(-2.360t)
the a(s) will cancel and we shall remain with:
1/2=e^-2.360t
introducing the natural logs we get:
ln (1/2)=ln e^(-2.360t)
ln(1/2)=-2.360t
hence;
t=(ln 0.5)/(-2.360)
t=0.294
the answer is t=0.294
Answer:
Step-by-step explanation:
Quadratic equation: ax² + bx + c = 0, where a ≠ 0
x² + 9x - 22
Factors of c (-22):
1 × -22 or -1 × 22
2 × -11 or -2 × 11
Sum of factors:
1 + (-22) = -21 or -1 + 22 = 21
2 + (-11) = -9 or -2 + 11 = 9
Table:
Hope this helps!
F(x)=(5x+1)(4x−8)(x+6)f, left parenthesis, x, right parenthesis, equals, left parenthesis, 5, x, plus, 1, right parenthesis, lef
andrey2020 [161]
Answer:
Step-by-step explanation:
Given 
The zeros of the polynomial function are the point where the function f(x) equals zero.
If abc=0, then a=0 or b=0 or c=0
Therefore:
Answer:
4x-y+1=0
Step-by-step explanation:
here,given equation of a line id
4x-y-2=0.. eqn(i)
equation of any line parallel to line (i) is
4x-y+k=0...eqn(ii)
since, the line(ii) passes through (1,5)[replacing x=1 and y=5 in eqn(ii), we get]
4*1-5+k=0
or, 4-5+k=0
or,-1+k=0
•°•k=1
substituting the value of k=1 in eqn(ii),
4x-y+1=0 is the required equation of the line.
