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Digiron [165]
3 years ago
12

Rohan is creating a presentation with at least 50 slides. He wants the slides to use a consistent layout and formatting. Which o

f the following parts of the presentation should he design first?
Computers and Technology
1 answer:
erma4kov [3.2K]3 years ago
4 0

The parts of the presentation that he should design first is Slide master

Slide master is a slide that enables you  to do the following:

•Modify your presentation to suit your taste

•It enables you to make  a partial or minor change  on the slide layout of your presentation

•Slide master  help you to  create a perfect and special  presentation.

•With Slide master  you can easily modify your slide text color.

Inconclusion The parts of the presentation that he should design first is Slide master.

Learn more about Slide master here:

brainly.com/question/12600334

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This program will store roster and rating information for a soccer team. Coaches rate players during tryouts to ensure a balance
Simora [160]

Answer:

// Scanner class is imported to allow program receive user input

import java.util.Scanner;

// class is defined

public class PlayerRoster {

   // main method that begin program execution

  public static void main(String[] args) {

   // Scanner object scan is defined

     Scanner scan = new Scanner(System.in);

   // multi-dimensional array to hold the jersey number and rating

     int[][] players = new int[5][2];

   // boolean flag to keep program alive

     boolean keepAlive = true;

   // the user input is declared as input of type char

     char input;

     

   // for loop that receive 5 player jersey number and ratings

   // it assigns the received input to the already initialized array

     for (int i = 0; i < 5; i++) {

        System.out.println("Enter player " + (i+1) + "'s jersey number: ");

        players[i][0] = scan.nextInt();

        System.out.println("Enter player " + (i+1) + "'s rating: ");

        players[i][1] = scan.nextInt();

        System.out.println();

     }

   // a blank line is printed

     System.out.println();

   // a method is called to display players array

     outputRoster(players, 0);

     

   // while the flag is true

   // display the Menu by calling the outputMenu method

     while (keepAlive) {

        outputMenu();

       // user input is assigned to input

        input = scan.next().charAt(0);

       //  if user input is 'q' then program will quit

        if (input == 'q') {

           keepAlive = false;

           break;

        }

       //  else if input is o, then outputRoaster is called to display players

        else if (input == 'o') {

           outputRoster(players, 0);

        }

       //  else if input is 'u', then user is allowed to edit a player rating

        else if (input == 'u') {

           System.out.println("Enter a jersey number: ");

           int jerseyNum = scan.nextInt();

           System.out.println("Enter a new rating for the player: ");

           int newRating = scan.nextInt();

           for (int l = 0; l < 5; l++) {

              if (players[l][0] == jerseyNum) {

                 players[l][1] = newRating;

              }

           }

        }

       //  else if input is 'a', user is allowed to add a new rating

        else if (input == 'a') {

           System.out.println("Enter a rating: ");

           int rating = scan.nextInt();

           outputRoster(players, rating);

        }

        // else if input is 'r', user is allowed to replace a player

        else if (input == 'r') {

           System.out.println("Enter a jersey number: ");

           int jerseyNum = scan.nextInt();

           boolean exists = true;

           for (int l = 0; l < 5; l++) {

              if (players[l][0] == jerseyNum) {

                 System.out.println("Enter a new jersey number: ");

                 players[l][0] = scan.nextInt();

                 System.out.println("Enter a rating for the new player: ");

                 players[l][1] = scan.nextInt();

              }

           }

           

        }

     }

     

     return;

  }

 

// this method take two parameters, players and min

// it then returns player with ratings greater than min

  public static void outputRoster(int[][] players, int min) {

     System.out.println(((min>0) ? ("ABOVE " + min) : ("ROSTER")));

     int item = 1;

     for (int[] player : players) {

        if (player[1] > min) {

           System.out.println("Player " + item + " -- Jersey number: " + player[0] + ", Rating: " + player[1]);

        }

        item++;

     }

     System.out.println();

  }

 

// outputMenu method to display the program menu

  public static void outputMenu() {

     System.out.println("MENU");

     System.out.println("u - Update player rating");

     System.out.println("a - Output players above a rating");

     System.out.println("r - Replace player");

     System.out.println("o - Output roster");

     System.out.println("q - Quit\n");

     System.out.println("Choose an option: ");  

  }

}

Explanation:

The program is written in Java and it is well commented.                                          

5 0
3 years ago
!!! 20 points !!!!!
puteri [66]

Answer: I need more info to answer this question

Explanation:

8 0
2 years ago
1. which of the following tools can be used to mesure mass. (answer = 5 +??? points)
krek1111 [17]
B. a triple-beam balance
4 0
3 years ago
Read 2 more answers
When presentations are being shown to an audience of over fifty people, how they should be displayed?
Anarel [89]
Full screeennn !!!!!!
6 0
3 years ago
Read 2 more answers
Using Amdahl’s Law, calculate the speedup gain of an application that has a 60 percent parallel component for (a) two processing
Nina [5.8K]

Answer:

a) Speedup gain is 1.428 times.

b) Speedup gain is 1.81 times.

Explanation:

in order to calculate the speedup again of an application that has a 60 percent parallel component using Anklahls Law is speedup which state that:

t=\frac{1 }{(S + (1- S)/N) }

Where S is the portion of the application that must be performed serially, and N is the number of processing cores.

(a) For N = 2 processing cores, and a 60%, then S = 40% or 0.4

Thus, the speedup is:

t = \frac{1}{(0.4 + (1-0.4)/2)} =1428671

Speedup gain is 1.428 times.

(b) For N = 4 processing cores and a 60%, then S = 40% or 0.4

Thus, the speedup is:

t=\frac{1}{(0.4 + (1-0.4)/4)} = 1.8181

Speedup gain is 1.81 times.

8 0
3 years ago
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