The advice is that she should not give up and that she should relax, and think of the time she comprehend more and then start to read. Another is to hire a private tutor to help or put her through.
<h3>What does a private tutor do?</h3>
A private tutor is known to be a person who is a specialist that has been trained in helping students known more and take in the concepts and details of any given course work.
Therefore, The advice is that she should not give up and that she should relax, and think of the time she comprehend more and then start to read. Another is to hire a private tutor to help or put her through and she will pass her exams in flying colors.
Learn more about private tutor from
brainly.com/question/6950210
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Note: The matrix referred to in the question is: ![M = \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]](https://tex.z-dn.net/?f=M%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2F2%261%2F3%260%5C%5C1%2F2%261%2F3%260%5C%5C0%261%2F3%261%5Cend%7Barray%7D%5Cright%5D)
Answer:
a) [5/18, 5/18, 4/9]'
Explanation:
The adjacency matrix is ![M = \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]](https://tex.z-dn.net/?f=M%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2F2%261%2F3%260%5C%5C1%2F2%261%2F3%260%5C%5C0%261%2F3%261%5Cend%7Barray%7D%5Cright%5D)
To start the power iteration, let us start with an initial non zero approximation,
![X_o = \left[\begin{array}{ccc}1\\1\\1\end{array}\right]](https://tex.z-dn.net/?f=X_o%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C1%5C%5C1%5Cend%7Barray%7D%5Cright%5D)
To get the rank vector for the first Iteration:

![X_1 = \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]\left[\begin{array}{ccc}1\\1\\1\end{array}\right] \\\\X_1 = \left[\begin{array}{ccc}5/6\\5/6\\4/3\end{array}\right]\\](https://tex.z-dn.net/?f=X_1%20%3D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2F2%261%2F3%260%5C%5C1%2F2%261%2F3%260%5C%5C0%261%2F3%261%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C1%5C%5C1%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5CX_1%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%2F6%5C%5C5%2F6%5C%5C4%2F3%5Cend%7Barray%7D%5Cright%5D%5C%5C)
Multiplying the above matrix by 1/3
![X_1 = \left[\begin{array}{ccc}5/18\\5/18\\4/9\end{array}\right]](https://tex.z-dn.net/?f=X_1%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%2F18%5C%5C5%2F18%5C%5C4%2F9%5Cend%7Barray%7D%5Cright%5D)
Answer:
The problem that created due to the difference in the model of programming language and the database model.
Explanation:
The practical relational model has three components which are as follows
1. Attributes
2. Datatypes
3. Tuples
To minimize this problem
1. We switch low pass L-Network to high pass L-network
2. We switch high pass L-Network to low pass L-network
3. We use the impedence matching transformer
Answer:
The answer to this question can be given as:
Method:
public static void showTwos(int number) //method definition.
{
method body.
System.out.print(number + " = "); //print number
while (number % 2 == 0) //condition
{
System.out.print("2 * "); //print message.
number = number / 2;
}
System.out.println(number); //print value.
}
Explanation:
In the above method definition firstly, we declare the method showTwos() that name is already given in the question then we pass a variable number as a parameter in the method. In this first, we take input number from the user and pass into this method. In this method we use a while loop it is an entry control loop in this loop first we modules the number if it is equal to 0.Then we divide the number by 2 and in the last, we print the value.