Simplify the expressions r-7+2r-12 10-4(3d-8) 7m=-5m+11m -(4x-5) +4(x+2)=6

Evan was carrying forward a balance of $300 from the previous month. His annual interest rate is 30%. Use computation to determi

sattari [20]

Answer:

The interest charged for this month is $7.5

Step-by-step explanation:

Given:

Principal = $300

Interest = 30%

Time = 1 month

To Find:

The interest charged for this month = ?

Solution:

we know that the interest charged = $principal \times \text {Interest rate} \times time$

1 month can also be written as $\frac{1}{12}$

Substituting the values,

interest charged:

=> $300 \times 30% \times \frac{1}{12}$

=> $300 \times \frac{30}{100} \times \frac{1}{12}$

=> $300 \times \frac{3}{120}$

=> $\frac{900}{120}$

=> $\frac{30}{4}$

=> $\frac{15}{2}$

=> 7.5

6 0

3 years ago

The base of a power is...

Bumek [7]

Answer:

The base of a power is the factor that is repeatedly multiplied by itself.

5 0

3 years ago

The domain of F(x) is the set of all numbers greater than or equal to 0 and less than it equal to 2

antoniya [11.8K]

Its false cause its not the set of all numbers

7 0

3 years ago

GIVING BRAINLIEST TO BEST ANSWER

ArbitrLikvidat [17]

Answer:

the triangle would be located at 3783<%*

3 0

3 years ago

The area of the rhombus is 540 cm2; the length of one of its diagonals is 4.5 dm. What is the distance between the point of inte

malfutka [58]

1. The area of the rhombus can be found by the formula

$A=\dfrac{d_1\cdot d_2}{2},$ where $d_1,\ d_2$ are rhombus's diagonals.

Note that $d_1=4.5\ dm=45\ cm,$ then

$540=\dfrac{45\cdot d_2}{2},\\ \\540\cdot 2=45d_2,\\ \\d_2=24\ cm.$

2. The diagonals of rhombus are perpendicular and are bisectors of each other. Then the triangle formed with halfs of diagonals is right triangles with legs

$\dfrac{d_1}{2}=22.5\ cm,\ \dfrac{d_2}{2}=12\ cm.$

The hypotenuse of this triangle is the rhombus's side. By the Pythagorean theorem

$\text{rhombus's side}^2=(22.5)^2+12^2=506.25+144=650.25,\\ \\\text{rhombus's side}=25.5\ cm.$

3. The distance between the point of intersection of the diagonals and the side of the rhombus is the height of right triangle considered above.

Use twice the Pythagorean theorem to find this height:

$\left\{\begin{array}{l}x^2+h^2=12^2\\(25.5-x)^2+h^2=22.5^2,\end{array}\right.$

where x is projection of leg 12 cm and h is height.

Subtract the first equation from the second:

$(25.5-x)^2+h^2-x^2-h^2=22.5^2-12^2,\\ \\650.25-51x=506.25-144,\\ \\51x=650.25-362.25=288,\\ \\x=\dfrac{96}{17}\ cm.$

Then

$h^2=144-\left(\dfrac{96}{17}\right)^2=144-\dfrac{9216}{289}=\dfrac{32400}{289},\\ \\h=\dfrac{180}{17}\ cm.$

Answer: $h=\dfrac{180}{17}\ cm.$

7 0

3 years ago

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