The domain of F(x) is the set of all numbers greater than or equal to 0 and less than it equal to 2

amm1812

24 bought 75, which, when multiplied out, equals 1800. 30 bought 60, which, when multiplied out, equals 1800.

1800+1800=3600.

3600*1/3=1200.

1200 cookies were returned.

5 0

4 years ago

Five companies (A, B, C, D, and E) that make elec- trical relays compete each year to be the sole sup- plier of relays to a majo

NNADVOKAT [17]

Answer:

a

$P(a | e') = 0.22$

$P(b | e') = 0.28$

$P(c | e') = 0.33$

b

$P(a | e' , d' , b') = 0.57$

Step-by-step explanation:

From the question we are told that

The probabilities are

Supplier chosen A B C

Probability P(a) = 0.20 P(b) = 0.25 P(c) = 0.15

D E

P(d) = 0.30 P(e) = 0.10

Generally the new probability of companies A being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(a | e') = \frac{P (a \ and \ e')}{P(e')}$

$P(a | e') = \frac{P (a)}{P(e')}$

$P(a | e') = \frac{P (a)}{1- P(e)}$

=> $P(a | e') = \frac{ 0.20}{1- 0.10}$

=> $P(a | e') = 0.22$

Generally the new probability of companies B being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(b | e') = \frac{P (b \ and \ e')}{P(e')}$

$P(b | e') = \frac{P (b)}{P(e')}$

$P(b | e') = \frac{P (b)}{1- P(e)}$

=> $P(b | e') = \frac{ 0.25}{1- 0.10}$

=> $P(b | e') = 0.28$

Generally the new probability of companies C being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(c | e') = \frac{P (c \ and \ e')}{P(e')}$

$P(c | e') = \frac{P (c)}{P(e')}$

$P(c | e') = \frac{P (c)}{1- P(e)}$

=> $P(c | e') = \frac{ 0.15}{1- 0.10}$

=> $P(c | e') = 0.17$

Generally the new probability of companies D being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(d | e') = \frac{P (d \ and \ e')}{P(e')}$

$P(d | e') = \frac{P (d)}{P(e')}$

$P(d | e') = \frac{P (d)}{1- P(e)}$

=> $P(d | e') = \frac{ 0.30}{1- 0.10}$

=> $P(c | e') = 0.33$

Generally the probability that B, D , E are not chosen this year is mathematically represented as

$P(N) = 1 - [P(e) +P(b) + P(d) ]$

=> $P(N) = 1 - [0.10 +0.25 +0.30 ]$

=> $P(N) = 0.35$

Generally the probability that A is chosen given that E , D , B are rejected this year is mathematically represented as

$P(a | e' , d' , b') = \frac{P(a)}{P(N)}$

=> $P(a | e' , d' , b') = \frac{0.20 }{0.35 }$

=> $P(a | e' , d' , b') = 0.57$

5 0

3 years ago

The net of a triangular prism is shown. Use the ruler provided to measure the dimensions of the net to the nearest half centimet

Black_prince [1.1K]

If the area of the triangle and the rectangle is 4 square cm and 2 square cm. Then the total surface area of the triangular prism will be 14 square cm.

<h3>What is a triangular prism?</h3>

A closed solid with two parallel triangular bases joined by a rectangle surface is known as a triangular prism.

The total surface area of the triangular prism will be

Total surface area = 2(area of the triangle) + 3(area of the rectangle)

The area of the rectangle will be

Rectangle area = 2 x 1

Rectangle area = 2 square cm

The area of the triangle will be

Triangle area = 0.5 x 4 x 2

Triangle area = 4 square cm

Then the total surface area will be

Total surface area = 2 x 4 + 3 x 2

Total surface area = 8 + 6

Total surface area = 14 square cm

More about the triangular prism link is given below.

brainly.com/question/24046619

#SPJ1

5 0

2 years ago

How can you use a pattern to add 20+30+40+50+60+70+80

Usimov [2.4K]

Answer:

$\displaystyle \: \: \: \: 7 \\ \: \: \sum \: (10n + 10) \\ n = 1$

Step-by-step explanation:

You can use Summation Notation as a pattern to evaluating "20 + 30 + 40 + 50 + 60 + 70 + 80":

$\displaystyle \: \: \: \: 7 \\ \: \: \sum \: (10n + 10) \\ n = 1$

I am joyous to assist you anytime.

8 0

3 years ago

Whos good at geometry? well feel free to help!

7nadin3 [17]

I’m good ik help you

6 0

3 years ago