1.
Han Solo genotype: ff
Offspring genotypes: Ff, ff
There is a 50% chance the child will have the force.
2.
Let f be webbed feet and F be non-webbed feet
Parental genotypes: ff ; FF
Possibility of webbed feet in offspring: 0%
3.
Yes, it is possible if both parents are heterozygous. 25% of offspring will be grey.
4.
Pheonotypes: Hairy and non-hairy fur
genotypes: HH, Hh, hh
5.
Parental genotypes: RR and RL
Offspring phenotypes: Brown hair and Brown and Black hair
Offspring genotypes: RR, RL
6.
Genotypes: BW
Phenotypes: Grey
7.
Black
8.
None of his children will be bald.<span />
Answer:
Transcription factors
Explanation:
They are part of the cell's core transcription toolkit, needed for the transcription of any gene. RNA polymerase binds to a promoter with help from a set of proteins called general transcription factors.
Answer:
True
Explanation:
To be favored in the wild is to be able to survive and reproduce therefore to be able to maintain a mate favors you.
Answer:
3/4
Explanation:
If we assume simple dominance and independent assortment for each trait, we can use Mendel's Law of Segregation to predict the phenotypic proportions in the offspring of the parental cross AABBCc x AabbCc.
<h3><u>Gene A</u></h3>
AA x Aa
- F1 genotypes: 1/2 AA, 1/2 Aa
- F1 phenotypes: all A
<h3 /><h3><u>Gene B</u></h3>
BB x bb
- F1 genotypes: 1 Bb
- F1 phenotypes: all B
<h3 /><h3><u>Gene C</u></h3>
Cc x Cc
- F1 genotypes: 1/4 CC, 2/4 Cc, 1/4 cc
- F1 phenotypes: 3/4 C, 1/4 cc
We want to know the proportion of progeny with all dominant phenotype (A_B_C_). Since the genes are independent, we can multiply the probabilities of each gene to obtain the overall probability of having a ABC progeny:
<h3>1 A_ x 1 B_ x 3/4 C_ = 3/4 A_B_C_</h3>