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sveticcg [70]
3 years ago
7

Give one and the main reason for an Endosperm in double fertilization in plants.

Biology
1 answer:
Nana76 [90]3 years ago
7 0

Answer:

Double fertilization gives stimulus to the plant that results in the development of the ovary into fruit and ovules into the seed.

Explanation:

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1. Han Solo and Leia fall madly in love and have one child (Ben). What is the chance that they will have a child who is strong w
Andreas93 [3]
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 Han Solo genotype: ff
Offspring genotypes: Ff, ff
There is a 50% chance the child will have the force.

2.
 Let f be webbed feet and F be non-webbed feet
Parental genotypes: ff ; FF
Possibility of webbed feet in offspring: 0%

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Yes, it is possible if both parents are heterozygous. 25% of offspring will be grey.

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Pheonotypes: Hairy and non-hairy fur
genotypes: HH, Hh, hh

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Parental genotypes: RR and RL
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Offspring genotypes: RR, RL

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Genotypes: BW
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7 0
3 years ago
What is a gene that has two positive transcription factors called
adoni [48]

Answer:

Transcription factors

Explanation:

They are part of the cell's core transcription toolkit, needed for the transcription of any gene. RNA polymerase binds to a promoter with help from a set of proteins called general transcription factors.

5 0
3 years ago
Sexual selection favors individuals with traits that increase their ability to obtain mates. True or False
jeka94

Answer:

True

Explanation:

To be favored in the wild is to be able to survive and reproduce therefore to be able to maintain a mate favors you.

7 0
3 years ago
Which of the following is consumed by the photosynthesis reaction occurring in plants?
Rufina [12.5K]
C carbon dioxide i think
3 0
3 years ago
Given the parents AABBCc × AabbCc, assume simple dominance for each trait and independent assortment. What proportion of the pro
Anit [1.1K]

Answer:

3/4

Explanation:

If we assume simple dominance and independent assortment for each trait, we can use Mendel's Law of Segregation to predict the phenotypic proportions in the offspring of the parental cross AABBCc x AabbCc.

<h3><u>Gene A</u></h3>

AA x Aa

  • F1 genotypes: 1/2 AA, 1/2 Aa
  • F1 phenotypes: all A
<h3 /><h3><u>Gene B</u></h3>

BB x bb

  • F1 genotypes: 1 Bb
  • F1 phenotypes: all B
<h3 /><h3><u>Gene C</u></h3>

Cc x Cc

  • F1 genotypes:  1/4 CC, 2/4 Cc, 1/4 cc
  • F1 phenotypes: 3/4 C, 1/4 cc

We want to know the proportion of progeny with all dominant phenotype (A_B_C_). Since the genes are independent, we can multiply the probabilities of each gene to obtain the overall probability of having a ABC progeny:

<h3>1 A_ x 1 B_ x 3/4 C_ = 3/4 A_B_C_</h3>
6 0
3 years ago
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