Answer:
The smallest value is 2) the opposite of 50 because it is farthest left of the zero (this makes it the smallest)
Step-by-step explanation:
1) = 100
2) = -50
3) = 0
4) = -25
5) = -5
Answer: 102
-----------------------------------------------
We'll use the formula
A = h*(b1+b2)/2
where
A = area of trapezoid
h = height
b1 & b2 are the parallel bases
In this case,
b1 = 6+7 = 13
b2 = 21
h = 6
Making the area to be
A = h*(b1+b2)/2
A = 6*(13+21)/2
A = 6*(34)/2
A = 204/2
A = 102
Side Note: We don't use the slanted side of 10 cm at all
The best way to approach this problem is to look at the graph of the given function. Replace values of x from 1 to 24 to indicate the numbers of hours in a day. As seen on the graph, there is only one point where the port is at high tide. That would be at 1:00 am.
Looking at the graph, it would be safe for the boats to be in the port when the graph levels off at around 10 to 24. That's from 10 am to before 12 midnight. Then, they would have to stay away between 12 midnight to before 10 am.
Set up a proportion:
4.1/22 = 12.3/x
Cross multiply:
4.1 * x = 22 * 12.3
4.1x = 270.6
Divide 4.1 to both sides:
x = 66