I think you divide 5/9 divided by 2/3.
5/9 divided by 2/3=4/3 simplified=2/3.
Just know I'm terrible at math so this could be like totally off the hook crazy and wrong.
Intercept at, y=0 and at x=0
-3(0)+5(y)=60
y=12 , z= 30, (y intercept) or (0,12,30)
-3(x)+5(0)=60
x=-20,z=30, (x intercept) or (-20, 0, 60)
Answer: V = 5.22m/s
Step-by-step explanation:
Given that the mass of the particles is proportional to the fifth power of the speed. That is
M = k V^5
Where M = mass and V = speed
K = constant of proportionality
A certain river normally flows at a speed of 3 miles per hour
V = 3 mph
M = unknown
M = k × 3^5
M = 243K
K = M/243 ........(1)
What must its speed be in order to transport particles that are 16 times as massive as usual
M = 16M
Using same formula
I.e M = KV^5
16M = M/243 × V^5
M will cancel out
16 = V^5/243
V^5 = 3888
V = 5.22m/s
2a+9 =4a-19
2a = 4a-19-9
2a-4a= -28
2a = -28
a = -14
Answer:
65 in²
Step-by-step explanation:
Area of a triangle = ½ × base × perpendicular height
= ½ × 13in × 10in
= 65 in²