Question

Helppppppppppppppppppp please

Answer 1

Answer:

$\sqrt[]{\frac{x+8}{4}}-3$

Step-by-step explanation:

$g(x)=4(x+3)^2-8$

First rewrite $g(x)$ as y

$y=4(x+3)^2-8$

Now swap y and x

$x=4(y+3)^2-8$

Add 8 on both sides.

$x+8=4(y+3)^2-8+8$

$x+8=4(y+3)^2$

Divide by 4.

$\frac{x+8}{4} =\frac{4(y+3)^2}{4}$

$\frac{x+8}{4}=(y+3)^2$

Extract the square root on both sides.

$\sqrt[]{\frac{x+8}{4}}=\sqrt[]{(y+3)^2}$

$\sqrt[]{\frac{x+8}{4}}=y+3$

Subtract 3 on both sides.

$\sqrt[]{\frac{x+8}{4}}-3=y+3-3$

$\sqrt[]{\frac{x+8}{4}}-3=y$