How do you solve this?
2 answers:
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Answer:
Step-by-step explanation:
As we can see it is a right angled triangle so
hypotenuse (h) = 14 . 7 km
perpendicular (p) = 11.9 km
base (b) = x
Now by using Pythagoras theorem
Hope it was helpful.:)
Draw dagarm (see attachment)
we've got a right triangle
the legs are 12 and 15
and the hypohuse is the diagonal
remember, for any right tirnalge
when the legs are a and b and hytponuse is c then
a²+b²=c²
so
12²+15²=c²
144+225=c²
369=c²
sqrt both sides
√369=c
3√41=c
the diagonal is 3√41 m or about 19.2m
we've got a right triangle
the legs are 12 and 15
and the hypohuse is the diagonal
remember, for any right tirnalge
when the legs are a and b and hytponuse is c then
a²+b²=c²
so
12²+15²=c²
144+225=c²
369=c²
sqrt both sides
√369=c
3√41=c
the diagonal is 3√41 m or about 19.2m