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2 years ago

Which equation is graphed in the figure?

Mathematics

2 answers:

stiks02 [169]2 years ago

6 0

Answer:

a. y=7/5x+2

Step-by-step explanation:

when trying to figure the answer to the question we have to consider whether the gradient is positive or negative and its y intercept

lines that slope from the top right to bottom left have a positive gradient and those that slope from the top left to bottom right have a negative gradient

remember the format for line equations is y=mx+c

m being the gradient and c being the y-intercept [where the line crosses the y axis]

looking at the slope of the line it has a positive gradient so b and d are not possible answers

now we have to look at the graph to find out the y-intercept

using the scale of 1 box is equivalent to i unit we find out it crosses the y-axis at (0,2) making the y intercept 2 eliminating c from being a possible answer making a the right answer

djyliett [7]2 years ago

5 0

Answer:

so the answer would be A. 7/5x +2

if you try graphing all the other equations it would be either over the picture or just not in the right place.

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A researcher was interested in comparing the resting heart rate of people who exercise regularly and people who do not exercise

alekssr [168]

Answer:

$t=\frac{(73.5-69.3)-0}{\sqrt{\frac{10.2^2}{16}+\frac{8.7^2}{12}}}}=1.173$

Using the critical value method we need to find a critical value in the t distribution who accumulates 0.025 of the area on the right and we got:

$t_{cric}= 2.06$

So then since our calculated value is lower then the critical value we fail to reject the null hypothesis and we can't conclude that the true mean resting pulse rate of people who do not exercise regularly is larger than the mean resting pulse rate of people who exercise regularly.

Step-by-step explanation:

Information given

$\bar X_{1}=73.5$ represent the mean for sample of people who do not exercise

$\bar X_{2}=69.3$ represent the mean for sample of people who do exercise

$s_{1}=10.2$ represent the sample standard deviation for 1

$s_{2}=8.7$ represent the sample standard deviation for 2

$n_{1}=16$ sample size for the group 1

$n_{2}=12$ sample size for the group 2

$\alpha=0.01$ Significance level

t would represent the statistic

System of hypothesis

We want to verify if the mean resting pulse rate of people who do not exercise regularly is larger than the mean resting pulse rate of people who exercise regularly, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2} \leq 0$

Alternative hypothesis: $\mu_{1} - \mu_{2}> 0$

The statistic for this case would be given by:

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

The degrees of freedom are given by:

$df=n_1 +n_2 -2=16+12-2=26$

Replacing the info given we got:

$t=\frac{(73.5-69.3)-0}{\sqrt{\frac{10.2^2}{16}+\frac{8.7^2}{12}}}}=1.173$

Using the critical value method we need to find a critical value in the t distribution who accumulates 0.025 of the area on the right and we got:

$t_{cric}= 2.06$

6 0

3 years ago

{8,2}and {6,-1} what’s the answer

ruslelena [56]

Answer:

-3/-2

Step-by-step explanation:

If you want to find the distance, the formula is y -y over x-x

6 0

3 years ago

Solve <br><br> 9x-14-2x=5(2x-6)

deff fn [24]

$9x-14-2x=5(2x-6)\qquad\text{use distributive property}\\\\(9x-2x)-14=(5)(2x)+(5)(-6)\\\\7x-14=10x-30\qquad\text{add 14 to both sides}\\\\7x=10x-16\qquad\text{subtract 10x from both sides}\\\\-3x=-16\qquad\text{divide both sides by (-3)}\\\\\boxed{x=\dfrac{16}{3}}$

8 0

3 years ago

I need help please?!!!

yanalaym [24]

Answer is: C

√11 ≈ 3.3661
Which the closest to your answers is 3.3

5 0

3 years ago

This equation will be in standard form if you subtract 2x2 from both sides and subtract 8x from both sides.

Lady_Fox [76]

i looked it up and it is false

6 0

3 years ago

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