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2 years ago

The opposite of -10 is 1.-(-(-10)) 2.-10 3.10 4.-|10|

Mathematics

2 answers:

Elanso [62]2 years ago

8 0

10 opposite of a negative is a positive!

IRISSAK [1]2 years ago

5 0

3. 10 because the opposite of a negative is a positive number

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What is the value of the expression below

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a=2,b=4. (3a+b)=3*2+4=10.

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Evaluate 5x2–3(x–2)+x for x=3

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10 (assuming you meant 5 TIMES 2

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Simplify the following algebraic expression:<br> 4+3 [6z - 5(6 +2z)]

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$\huge\text{Hey there!}$

$\huge\text{4+3 [6z - 5(6 +2z)]}$

$\huge\text{4+(3)(6z)+(3)(-5(6+2z))}\\\\\rightarrow\huge\text{4+18z+(-30z)+(-90)}$

$\huge\text{\bf{Combine the like terms if you have any.}}$

$\huge\text{Like term \#1: 10z \& -30z}\\\\\\\huge\text{Like term \#2: 4 \& -90}$

$\huge\text{18z + (-30z) + (4 + (-90))}$

$\huge\text{18z + (-30z) = -12z}\\\\\\\huge\text{4 + (-90) = -86}$

$\boxed{\boxed{\huge\text{Answer: -12z + (-86)}}}\huge\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{LoveYourselfFirst:)}$

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3 years ago

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An article reports that 1 in 500 people carry the defective gene that causes inherited colon cancer. In a sample of 2000 individ

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Answer:

a) P=0.558

b) P=0.021

Step-by-step explanation:

We can model this random variable as a Poisson distribution with parameter λ=1/500*2000=4.

The approximate distribution of the number who carry this gene in a sample of 2000 individuals is:

$P(x=k)=\frac{\lambda^ke^{-\lambda}}{k!} =\frac{4^ke^{-4}}{k!}$

a) We can calculate that the approximate probability that between 4 and 9 (inclusive) as:

$P(4\leq x\leq 9)=\sum_{k=4}^9P(k)\\\\\\ P(4)=4^{4} \cdot e^{-4}/4!=256*0.0183/24=0.195\\\\P(5)=4^{5} \cdot e^{-4}/5!=1024*0.0183/120=0.156\\\\P(6)=4^{6} \cdot e^{-4}/6!=4096*0.0183/720=0.104\\\\P(7)=4^{7} \cdot e^{-4}/7!=16384*0.0183/5040=0.06\\\\P(8)=4^{8} \cdot e^{-4}/8!=65536*0.0183/40320=0.03\\\\P(9)=4^{9} \cdot e^{-4}/9!=262144*0.0183/362880=0.013\\\\\\$

$P(4\leq x\leq 9)=\sum_{k=4}^9P(k)=0.195+0.156+0.104+0.060+0.030+0.013=0.558$

b) The approximate probability that at least 9 carry the gene is:

$P(x\geq9)=1-P(x\leq 8)\\\\\\$

$P(0)=4^{0} \cdot e^{-4}/0!=1*0.0183/1=0.018\\\\P(1)=4^{1} \cdot e^{-4}/1!=4*0.0183/1=0.073\\\\P(2)=4^{2} \cdot e^{-4}/2!=16*0.0183/2=0.147\\\\P(3)=4^{3} \cdot e^{-4}/3!=64*0.0183/6=0.195\\\\P(4)=4^{4} \cdot e^{-4}/4!=256*0.0183/24=0.195\\\\P(5)=4^{5} \cdot e^{-4}/5!=1024*0.0183/120=0.156\\\\P(6)=4^{6} \cdot e^{-4}/6!=4096*0.0183/720=0.104\\\\P(7)=4^{7} \cdot e^{-4}/7!=16384*0.0183/5040=0.06\\\\P(8)=4^{8} \cdot e^{-4}/8!=65536*0.0183/40320=0.03\\\\$

$P(x\geq9)=1-P(x\leq 8)\\\\P(x\geq9)=1-(0.018+0.073+0.147+0.195+0.195+0.156+0.104+0.060+0.030)\\\\P(x\geq9)=1-0.979=0.021$

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3 years ago

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