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leonid [27]
3 years ago
10

What is the equation of a line, in general form, that passes through points (-1, 2) and (5, 2)? y - 2 = 0 x - 2 = 0 y - x - 2 =

0
Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
7 0

Answer:

y- 2=0

Step-by-step explanation:

Given  : A  line passes through points (-1, 2) and (5, 2).

To find : What is the equation of a line.

Solution : We have given points (-1, 2) and (5, 2).

General form of line equation :

y-y_{1} =(\frac{y_{2}-y_{1}}{x_{2}-x_{1}})(x-x_{1}).

Here, y_{1} = 2.\\y_{2} =2\\x_{1} =-1\\x_{2} =5.

Plug the values

y- 2 =(\frac{2-2}{5+1})(x+ 1).

y- 2=0.

Therefore, y- 2=0.

enot [183]3 years ago
4 0

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-1, 2) and (5, 2). Substitute:

m=\dfrac{2-2}{5-(-1)}=\dfrac{0}{6}=0\\\\y-2=0(x-(-1))\\\\y-2=0

<h3>Answer: y - 2 = 0.</h3>
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<u>Step-by-step explanation:</u>

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Next, replace "y" with -2 into either of the original equations to solve for x:

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2x + 10 = 2

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<u>Check:</u>

Plug in the x- and y-values into the other original equation:

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