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fiasKO [112]
3 years ago
13

A round patio is 14 m in diameter. what is the distance around the patio

Mathematics
2 answers:
NeTakaya3 years ago
5 0
You would need to find the circumstance which the formula is pi*D. with D being the diameter. you would multiply 14 by 3.14 and get 43.96. Therefore the circumstance would be 43.96. hope this helped
mixas84 [53]3 years ago
5 0
Since it is round, it is a circle.

Distance round a circle is the perimeter. Perimeter of a circle is = πd

where d = diameter.

Perimeter =  πd =  π*14 = <span> 14π

Perimeter </span>≈ 14 * 3.14159 ≈ 43.98226

Distance around the patio ≈ 43.98 m.
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Read 2 more answers
A school has a parking lot that is 150.23 feet by 135.12 feet. What is the perimeter of the parking lot?
elena-14-01-66 [18.8K]

Answer: 570.70 ft

Step-by-step explanation:

The perimeter is the distance around the entire parking lot.

The measurement of 150.23 ft by 135.12 ft is half of the distance of the lot because it represents just two sides yet there are 4 sides.

The other two sides have the same measurement as this is a rectangle.

The perimeter of the parking lot is:

= (150.23 * 2) + (135.12 * 2)

= 570.70 ft

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3 years ago
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5 0
2 years ago
In a doctor's waiting room, there are 14 seats in a row. Eight people are waiting to be seated. Three of the 8 are in one family
lianna [129]
There are 14 chairs and  8 people to be seated. But among the 8. three will be seated together:

So 5 people and (3) could be considered as 6 entities:

Since the order matters, we have to use permutation:

¹⁴P₆ = (14!)/(14-6)! = 2,162,160, But the family composed of 3 people can permute among them in 3! ways or 6 ways. So the total number of permutation will be ¹⁴P₆  x 3! 

2,162,160 x 6 = 12,972,960 ways.

Another way to solve this problem is as follow:

5 + (3) people are considered (for the time being) as 6 entities:

The 1st has a choice among 14 ways
The 2nd has a choice among 13 ways
The 3rd has a choice among 12 ways
The 4th has a choice among 11 ways
The 5th has a choice among 10 ways
The 6th has a choice among 9ways

So far there are 14x13x12x11x10x9 = 2,162,160 ways
But the 3 (that formed one group) could seat among themselves in 3!
or 6 ways:

Total number of permutation = 2,162,160 x 6 = 12,972,960

4 0
2 years ago
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