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Aliun [14]
3 years ago
9

Plzzzzzzzzzzzz help fast

Mathematics
2 answers:
Oduvanchick [21]3 years ago
7 0

y = 2x^2 - 4

Add both side 4

y + 4 = 2x^2 - 4 + 4

y + 4 = 2x^2

Divide both sides by 2

( y + 4 ) ÷ 2 = 2x^2 ÷ 2

y + 4 / 2 = x^2

x^2 = y + 4 / 2

x = + √(y+4/2) Or x = - √(y+4/2)

Thus the <em><u>second option</u></em> is the correct answer.

Licemer1 [7]3 years ago
4 0

COPYING IS NOT AT ALL GOOD MY BOY ! TRY TO CHANGE THAT HABIT

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The number 1.3,1/1/3,1.34 in least to greatest
elixir [45]
1.3, 1 1/3, 1.34

The decimal version of 1 1/3 is 1.333 (so on)

so 1.3 is less than 1.333 and 1.333 is less than 1.34

1.3<1.333<1.34
4 0
4 years ago
Нужно срочное подробное решение заданий с подробным обьяснением<br> !!!Дам 20 очков!!!
Sergeeva-Olga [200]

Answer:whaaaat?

Step-by-step explanation:

5 0
3 years ago
A positive integer is twice another.the sum of the reciprocal of the two positive integer is 3/14. Find the integers
icang [17]

Answer:

\huge\boxed{14\ \text{and}\ 7}

Step-by-step explanation:

n,\ m-\text{positive integer}\\\\n=2m-\text{a positive integer is twice another}\\\\\dfrac{1}{n}+\dfrac{1}{m}=\dfrac{3}{14}-\text{the sum of the reciprocal of the two positive integer is }\ \dfrac{3}{14}\\\\\text{We have the system of equations:}\\\\\left\{\begin{array}{ccc}n=2m&(1)\\\dfrac{1}{n}+\dfrac{1}{m}=\dfrac{3}{14}&(2)\end{array}\right

\text{Substitute (1) to (2):}\\\\\dfrac{1}{2m}+\dfrac{1}{m}=\dfrac{3}{14}\\\\\dfrac{1}{2m}+\dfrac{1\cdot2}{m\cdot2}=\dfrac{3}{14}\\\\\dfrac{1}{2m}+\dfrac{2}{2m}=\dfrac{3}{14}\\\\\dfrac{1+2}{2m}=\dfrac{3}{14}\\\\\dfrac{3}{2m}=\dfrac{3}{14}\Rightarrow2m=14\qquad\text{divide both sides by 2}\\\\\dfrac{2m}{2}=\dfrac{14}{2}\\\\\boxed{m=7}

\text{Substitute it to (1):}\\\\n=2\cdot7\\\\\boxed{n=14}

8 0
3 years ago
The function f(x)= -6x+11 has a range given by {-37,-25,-13,-1}.Select the domain values of the function from the list 1,2,3,4,5
andreev551 [17]
The range is {-37,-25,-13,-1}. So you need to figure out what four numbers from this list of numbers (1,2,3,4,5,6,7,8), when applied to this
function, ( f(x)=-6x+11 ), equals these numbers that are in the range {-37,-25,-13,-1}.

So you apply each of these numbers (1,2,3,4,5,6,7,8) into the function (f(x)=-6x+11)
one by one.

f(1)=-6(1)+11=5
f(2)=-6(2)+11= -1
f(3)=-6(3)+11= -7
f(4)=-6(4)+11= -13
f(5)=-6(5)+11= -19
f(6)=-6(6)+11= -25
f(7)=-6(7)+11= -31
f(8)=-6(8)+11= -37
As you can see, f(2),f(4),f(6),and f(8) equal the numbers that are in the range {-37,-25,-13,-1}.
4 0
3 years ago
-3x+18=7x what could you do to isolate the variable term to one side of the equation
Alexxandr [17]

Answer:

7x=−x+24 7 x = − x + 24  

Step-by-step explanation:

The equations we solved in the last section simplified nicely so that we could use the. Our strategy will involve choosing one side of the equation to be the variable side, and step by step, to isolate the variable terms on one side of the equation

7 0
3 years ago
Read 2 more answers
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