3%
Answer:
Selling price with VAT {15%} = Rs 41400
S.P +15% of S.P =Rs 41400
S.P(1+15%)=Rs 41400
S.P=Rs 41400/1.15
Selling price without VAT =Rs 36000
Again
Discount = 10%
M.P =S.P+ Discount % of M.P
M.P-Discount% of M.P= S.P
M.P(1-Discount%)=Rs 36000
M.P(1-10%)=Rs 36000
M.P=Rs 36000/0.9
Marked Price = Rs 40,000
again
Discount =Discount % of M.P
=10% of 40000
=Rs 4,000
Again
Profit=20%
For 20% profit
Cost price = (S.P*100)/(100+profit%)
=(36000*100)/(100+20)
= Rs 30000
For 24% profit
selling price = (100+profit%)*C.P/100
=(100+24)*30000/100
=Rs 37200
Again
Discount = 40000–37200 = Rs2800
Discount % = discount/M.P*100%
=2,800/40,000* 100 = 7%
Finally
Discount percent to be reduced =10%–7%= 3%
The total number of miles wallked = 3.74 + 5.5 = 9.25 miles.
The amount his parent donated was $175,
amount pay for each mile = 175/9.25 = $ 18.92.
For this case, the first thing we must do is define variables.
We have then:
d: number of dimes
q: number of quarters
We now write the system of equations that models the problem.
We have then:
He has a total of 30 coins:

The toal value of Kyles coins is $ 4.80:

Answer:
A system of equations that can be used to find the number of dimes, d, and the number of quarters, q, kyes has is:


When we sort the terms in descending order, we get 3x^6 - 4x^3 + 8x + 9
The exponents decrease (from 6 to 3 to 1 to 0) with the largest exponent term on the left side and the smallest on the right side.
Fill in the missing terms to get 3x^6 + 0x^5 + 0x^4 + (-4x^3) + 0x^2 + 8x^1 + 9x^0
So the sequence of coefficients are 3, 0, 0, -4, 0, 8, 9
It can be useful to know the prime factorization of the number:

Then, remember that the n-th root of a number is the same as that number to the 1/n-th power:
![\sqrt[4]{256} = 256^{\frac{1}{4}}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B256%7D%20%3D%20256%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D)
Finally, you have to remember the rule for raising a power to another power, i.e. you multiply the exponents:

Put together everything we said so far to write
![\sqrt[4]{256} = 256^{\frac{1}{4}} = (2^8)^{\frac{1}{4}} = 2^{\frac{8}{4}} = 2^2 = 4](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B256%7D%20%3D%20256%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%20%3D%20%282%5E8%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%20%3D%202%5E%7B%5Cfrac%7B8%7D%7B4%7D%7D%20%3D%202%5E2%20%3D%204%20)