Answer:
Suppose the heights of 18-year-old men are approximately normally distributed, with mean 71 inches and standard deviation 4 inches.
(a) What is the probability that an 18-year-old man selected at random is between 70 and 72 inches tall? (Round your answer to four decimal places.)
z1 = (70-71)/4 = -0.25
z2 = (72-71/4 = 0.25
P(70<X<72) = p(-0.25<z<0.25) = 0.1974
Answer: 0.1974
(b) If a random sample of thirteen 18-year-old men is selected, what is the probability that the mean height x is between 70 and 72 inches? (Round your answer to four decimal places.)
z1 = (70-71)/(4/sqrt(13)) = -0.9014
z2 = (72-71/(4/sqrt(13)) = 0.9014
P(70<X<72) = p(-0.9014<z<0.9014) = 0.6326
Answer: 0.6326
please mark me the brainiest
Answer:
hope that helps
Step-by-step explanation:
3x^2+2xy+y2=2
6x + 2y + 2xy' + 2yy' = 0
x=1 ==> y=-1
6(1) + 2(-1) + 2(1)y' + 2(-1)y' = 0
6 - 2 + 2y' - 2y' = 0
4 = 0
(e) undefined
The graph is an ellipse. At (1,-1) there is a vertical tangent
The answer is B. I hope this helped :)
So,
I like to simplify a fraction first. This is what I do when I'm in a store trying to find the unit price.

Factor.

Cross out ones.

Multiply it out.

In my head, I remember that one-eighth is equal to 0.125.
So seven-eighths is equal to 0.125 times 7.
0.125 * 7 = 0.875
Convert to percent form.
0.875 --> 87.5%
James answered 87.5% of his quiz correctly.
I actually have the decimal equivalents for eighths in my head when I'm shopping. So once I get seven-eighths, I immediately know how much that is. I can also subtract 0.125 from 1.000 to get seven-eighths.