Find the mode of the data of 10 12 11 10 7 6 7

In the number 3,287,854 how many times greater is the value of the 8 in the ten thousands place compared to the value of the 8 i

olga55 [171]

8 in the 10,000s place is worth 80,000.

8 in the hundreds place is worth 800.

80,000/800 = 100

Answer: 100 times.

6 0

3 years ago

Read 2 more answers

In 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hir

Ede4ka [16]

Answer:

Explained below.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}= p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

(a)

The sample selected is of size n = 450 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

$\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{450}}=0.0204$

So, the sampling distribution of sample proportion is $\hat p\sim N(0.75,0.0204^{2})$ .

(b)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

$P(p-0.04$

$=P(-1.96$

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.95.

(c)

The sample selected is of size n = 200 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

$\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{200}}=0.0306$

So, the sampling distribution of sample proportion is $\hat p\sim N(0.75,0.0306^{2})$ .

(d)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

$P(p-0.04$

$=P(-1.31$

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.81.

(e)

The probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 450 is 0.95.

And the probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 200 is 0.81.

So, there is a gain in precision on increasing the sample size.

6 0

3 years ago

Find the solution of this system of equations.

vagabundo [1.1K]

I'm going to use the substitution method.

4x + 4y = -16
-8x - 6y = -20

4x + 4y = -16
- 4x - 4x
--------------------------
4y = -4x - 16
------ ------ ------
4 4 4

y = -x - 4

-8x - 6(-x - 4) = -20
-8x + 6x + 24 = -20
-2x + 24 = -20
- 24 - 24
----------------------------
-2x = 44
------- -------
2 2

x = 22

4(22) + 4y = -16
88 + 4y = -16
- 88 - 88
------------------------
4y = -104
------ ---------
4 4

y = -26

The answer is (22, -26).

4 0

3 years ago

Solve the system of equations by elimination. 2x+8y=10 -4x-9y=-13 x = y =

Reptile [31]

So use cancelation
multiply first equation by 2
2x+8y=10
times 2
4x+16y=20
now add

4x+16y=20
-4x-9y=-13 +
0x+7y=7
7y=7
divide by 7
y=1

subsittue

2x+8y=10
2x+8(1)=10
2x+8=10
subtract 8 from both sides
2x=2
divide by 2
x=1

x=1
y=1

8 0

3 years ago

Please help, will mark brainliest

Delicious77 [7]

Sorry it took so long, here is your answer:

5 0

3 years ago

Find the mode of the data of 10 12 11 10 7 6 7​

Find the mode of the data of 10 12 11 10 7 6 7