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Rudik [331]
3 years ago
10

In a group of twelve people, four had been selected for a transfer. If two of the twelve are selected, what is the probability t

hat both of those selected are selected for a
transfer?
Mathematics
1 answer:
rusak2 [61]3 years ago
3 0

Answer:

1/11

Step-by-step explanation:

The probability the first person has been selected for transfer is 4/12.

The probability the second person has been selected for transfer is 3/11.

So the probability of both is 4/12 × 3/11 = 1/11.

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Answer:

DG = 30

Step-by-step explanation:

Given:

DH = 6

DE = 4

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Required:

DG

Solution:

DG = DH + HG

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Let's find HG

Given that HE is parallel to the third side of ∆DGF, based on the side-splitter theorem, the other two sides of ∆DGF are divided proportionally.

Therefore,

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