In a group of twelve people, four had been selected for a transfer. If two of the twelve are selected, what is the probability t
hat both of those selected are selected for a
transfer?
1 answer:
Answer:
1/11
Step-by-step explanation:
The probability the first person has been selected for transfer is 4/12.
The probability the second person has been selected for transfer is 3/11.
So the probability of both is 4/12 × 3/11 = 1/11.
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The difference between a zero and one, and b negative four and six is negative five and eight
The answer to your question is 45 ✌️
Option C
<u>SOLUTION:</u>
We need to find the value of B - CF
First find the value CF:
![CF=\left[\begin{array}{ccc}12&0&1.5\\1&-6&7\\\end{array}\right] \left[\begin{array}{ccc}-2&0\\0&8\\2&1\end{array}\right]](https://tex.z-dn.net/?f=CF%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%260%261.5%5C%5C1%26-6%267%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%260%5C%5C0%268%5C%5C2%261%5Cend%7Barray%7D%5Cright%5D)
![CF=\left[\begin{array}{ccc}12(-2)+0 *0+1.5*2&12*0+0.8+1.5*1\\1*(-2)+(-6)*0+7.2&1*0+(-6)*8+7.1\\\end{array}\right]](https://tex.z-dn.net/?f=CF%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%28-2%29%2B0%20%2A0%2B1.5%2A2%2612%2A0%2B0.8%2B1.5%2A1%5C%5C1%2A%28-2%29%2B%28-6%29%2A0%2B7.2%261%2A0%2B%28-6%29%2A8%2B7.1%5C%5C%5Cend%7Barray%7D%5Cright%5D)
![CF=\left[\begin{array}{ccc}-21&1.5\\12&-41\\\end{array}\right]](https://tex.z-dn.net/?f=CF%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-21%261.5%5C%5C12%26-41%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Now find value of B - CF:
![B-CF=\left[\begin{array}{ccc}2&8\\6&3\\\end{array}\right] -\left[\begin{array}{ccc}-21&1.5\\12&-41\\\end{array}\right]](https://tex.z-dn.net/?f=B-CF%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%268%5C%5C6%263%5C%5C%5Cend%7Barray%7D%5Cright%5D%20-%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-21%261.5%5C%5C12%26-41%5C%5C%5Cend%7Barray%7D%5Cright%5D)
![B-CF=\left[\begin{array}{ccc}23&6.5\\-6&44\\\end{array}\right]](https://tex.z-dn.net/?f=B-CF%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D23%266.5%5C%5C-6%2644%5C%5C%5Cend%7Barray%7D%5Cright%5D)
∴ the value of B - CF is ![\left[\begin{array}{ccc}23&6.5\\-6&44\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D23%266.5%5C%5C-6%2644%5C%5C%5Cend%7Barray%7D%5Cright%5D)
<em>I hope this helps....</em>
Answer:
712
Step-by-step explanation:
So what you do is you have to substitute -9 for a and -4 b.
7(-4)^2 +5((-9)(-4)-6)=
=7(16)+5(30)=
=112+600=
=712
Answer:
I think it's D. hope it helps
