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Ymorist [56]
3 years ago
9

Volunteers at an animal shelter are building a rectangular dog run so that one shorter side of the rectangle is formed by the sh

elter building as shown. They plan to spend between $100 and $200 on fencing for the sides at a cost of $2.50 per ft. Write and solve a compound inequality to model the possible length of the dog run. ​

Mathematics
1 answer:
Shkiper50 [21]3 years ago
8 0

Write and solve a compound inequality to model the possible length of the dog run.

The inequality to model the possible length of the dog run is;. 100 ≤ 2.50x ≥ 200

And the possible length of the dog run is 80ft.

Minimum spending = $100

Maximum spending = $200

Cost per square feet = $2.50

let

x = possible number of square feet

The inequality:

100 ≤ 2.50x ≥ 200

This means possible number of square feet constructed is greater than or equal to $100 or less than or equal to $200

solve:

100 ≤ 2.50x ≥ 200

divide the inequality into 2

100 ≤ 2.50x

x ≤ 100/2.5

x ≤ 40

the other part:

2.50x ≥ 200

x ≥ 200/2.50

x ≥ 80

Therefore,

the possible length of the dog run is 80 feet

Read more:

brainly.com/question/9135876

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You are told to ignore the amount of principal paid, so you are apparently to assume the loan amount was for $50 thousand.

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b) The new monthly payment is $11.72×50 = $586.00

c) The increase in monthly payment is figured in the usual way:

... (new/old -1)×100% = (1.0984-1)×100% = 9.84%

_____

In reality, about 3% of the loan will have been paid at the end of 2 years. Thus, the original loan amount may have been near $51,500. This problem is telling you to ignore the difference.

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3 years ago
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Which is the degree measure of an angle whose tangent is 5.67?
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80 degrees.

Step-by-step explanation:

7 0
3 years ago
Use summation notation to write the series 49 + 54 + 59 +... for 14 terms.
My name is Ann [436]

Answer:

Arithmetic sequence states that a sequence of numbers such that the difference between the consecutive terms is constant.

it is given by:  a_n = a+(n-1)d where a is the first term , n is the number of term and d is the common difference.

Given the series: 49 + 54 + 59+ ......

here, Common difference(d) = 5

First term(a) = 49

by definition we have;

For nth term

a_n = a+(n-1)d

a_n = 49+(n-1)5

a_n =49+5n -5 = 5n + 44

To write the series using summation notation for 14 terms

Summation symbol '\sum'

The series for 14th terms is given by;

\sum_{n=1}^{14}(5n +44)


5 0
3 years ago
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A market research team compiled the following discrete probability distribution, where X represents the number of automobiles ow
rodikova [14]

Answer:

The standard deviation of X is 0.7

Step-by-step explanation:

We are given the following distribution:

    x:     0        1         2       3    

P(x):    0.3     0.5     0.2     0.4

We have to find the standard deviation of X.

Formula:

E(x) = \displaystyle\sum x_iP(x_i)\\\\E(x) =0(0.3) + 1(0.5) + 2(0.2) + 3(0.4)\\\\E(x) = 2.1\\\\E(x^2) = \displaystyle\sum x_i^2P(x_i)\\\\E(x^2) =0(0.3) + 1(0.5) + 4(0.2) + 9(0.4)\\\\E(x^2) = 4.9\\\\Var(x) = E(x^2) - (E(x))^2 = 4.9-(2.1)^2 = 0.49\\\\\sigma(x) = \sqrt{Var(x)} =\sqrt{0.49} = 0.7

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6 0
3 years ago
9 friends are lining up. Joe, Susan, John, and Meredith must be beside each other. How many ways can they line up?
ZanzabumX [31]
<h3>Answer:  17,280</h3>

This is one single number slightly over 17 thousand.

You may need to erase the comma when typing the answer in.

=========================================================

Explanation:

Let's say that another person steps in for Joe, Susan, John, and Meredith. I'll refer to this person as the teacher (perhaps these 9 friends are students on a field trip).

The 9 friends drops to 9-4 = 5 people when those four named people leave the group temporarily. Then it bumps up to 5+1 = 6 people when the teacher steps in. Wherever the teacher is located, the four friends that left will replace the teacher. This guarantees that those four friends stick together.

There are 6! = 6*5*4*3*2*1 = 720 ways to arrange those 6 people. The exclamation mark is a factorial symbol.

Within any of those 720 permutations, we have 4! = 4*3*2*1 = 24 ways to arrange those group of named people when they come back to replace the teacher.

So overall the answer is 4!*6! = 24*720 = 17,280

You may need to erase the comma when typing the answer in.

-------------

Side note: There are 9! = 362,880 ways to arrange all nine friends regardless if those four mentioned people stick together or not. We see that they stick together roughly (17,280)/(362,880) = 0.0476 = 4.76% of the time.

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3 years ago
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