Answer:
It can be expressed in 2 ways horizontal and vertical ways.
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page layout...... im not sure
Answer:
The answer is below
Explanation:
Given that:
Frame transmission time (X) = 40 ms
Requests = 50 requests/sec, Therefore the arrival rate for frame (G) = 50 request * 40 ms = 2 request
a) Probability that there is success on the first attempt = 
but k = 0, therefore Probability that there is success on the first attempt = 
b) probability of exactly k collisions and then a success = P(collisions in k attempts) × P(success in k+1 attempt)
P(collisions in k attempts) = [1-Probability that there is success on the first attempt]^k = ![[1-e^{-G}]^k=[1-0.135]^k=0.865^k](https://tex.z-dn.net/?f=%5B1-e%5E%7B-G%7D%5D%5Ek%3D%5B1-0.135%5D%5Ek%3D0.865%5Ek)
P(success in k+1 attempt) =
Probability of exactly k collisions and then a success = 
c) Expected number of transmission attempts needed = probability of success in k transmission = 
Answer:
To save the course object instances in an array, use;
Course[] courses = new Course[7];
courses[0] = new Course("IT 145");
courses[1] = new Course("IT 200");
courses[2] = new Course("IT 201");
courses[3] = new Course("IT 270");
courses[4] = new Course("IT 315");
courses[5] = new Course("IT 328");
courses[6] = new Course("IT 330");
Explanation:
The java statement above assigns an array of size 7 with the course class constructor, then order courses are assigned to the respective indexes of the new array.
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