Find the distance between (5, -4) and (-1, -2)
1 answer:
Answer: The distance is sqrt(40).
Step-by-step explanation:
Let's use the Pythagorean Theorem (a^2 + b^2 = c^2)
(Look at the image I attached)
Let's set a = 2 and b = 6. The mystery side is c, which is opposite to the right angle that is formed when you draw perpendicular lines from each of the points.
(2)^2 + (6)^2 = c^2 <--- First, we need to simplify
4 + 36 = c^2
40 = c^2 <--- Now, we need to take the square root of both sides.
c = sqrt(40)
So, the distance between (5, -4) and (-1, -2) is sqrt(40). I recommend looking at some videos on Khan Academy if you need more help! Let me know if you want me to attach a link that you can visit.
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Answer:
(b) {-8, 2}
Step-by-step explanation:
The given equation
x³ +6x -16 = 0
cannot be factored in integers. It has one irrational real root near x=1.759, and two complex roots.
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Perhaps you want to factor ...
x² +6x -16 = 0
(x +8)(x -2) = 0
This has solutions x = -8 and x = 2 that make the factors be zero.
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<em>Additional comment</em>
"Cubed" refers to an exponent of 3.
