The sum clearly diverges. This is indisputable. The point of the claim above, that

is to demonstrate that a sum of infinitely many terms can be manipulated in a variety of ways to end up with a contradictory result. It's an artifact of trying to do computations with an infinite number of terms.
The mathematician Srinivasa Ramanujan famously demonstrated the above as follows: Suppose the series converges to some constant, call it

. Then

Now, recall the geometric power series

which holds for any

. It has derivative

Taking

, we end up with

and so

But as mentioned above, neither power series converges unless

. What Ramanujan did was to consider the sum

as a limit of the power series evaluated at

:

then arrived at the conclusion that

.
But again, let's emphasize that this result is patently wrong, and only serves to demonstrate that one can't manipulate a sum of infinitely many terms like one would a sum of a finite number of terms.
Answer:
B.
Step-by-step explanation:
A parameter is a summary measure computed to describe a characteristic of the population and it involves the measurement of all in the population numerically/quantitatively. e.g Average of all the values measured in the population
A statistic is a measurement based on sample observations.
Examples of statistics constructed from a random sample : [ 
(a) max
(b) Average of the observed values
(c) Range = max - min
Step-by-step explanation:
I cant show a number line so i'll do my best to explain how its graphed.
15) x - 1 < 15
add 1 to both sides:
x < 16
Because it is less than, rather than less than or equal to, it's graphed with an open circle (not filled in) on 16, and everything less than 16 highlighted
---------------------------------------------------------
16) 2(y + 1) - 2 ≥ 12
distribute the 2:
2y + 2 - 2 ≥ 12
combine like terms
2y ≥ 12
isolate y:
y ≥ 6
This one is greater than or equal to, so it's graphed with a closed circle (filled in) and everything above 6 highlighted
So leangh of ladder=2x+1
bottom edgre=x-1
wall edge=2x
so therefor, since this is a right triangle, use pythagorean theorem
a^2+b^2=c^2
c=hypotonues=longest side
b and a=sides touching the right angle
so x-1 and 2x are a and b
2x+1=c
subsitute
(x-1)^2+(2x)^2=(2x+1)^2
x^2-2x+1+4x^2=4x^2+4x+1
add like terms
5x^2-2x+1=4x^2+4x+1
subtract 1 from both sdies
5x^2-2x=4x^2+4x
subtract 4x from both sdies
5x^2-6x=4x^2
subtract 4x^2 from both sides
x^2-6x =0
factor out the x using distributive property which is
ab+ac=a(b+c)
x^2-6x=x(x-6)
(x)(x-6)=0
if xy=0 then assume x and/or y=0
x=0
we remember that one of the side legnths is 2x and if x=0 then the side legnth=0 which is not possible, so we discard
x-6=0
add 6 to both sides
x=6
subsitute and solve
legnth of ladder=2x+1
x=6 subsitute
2(6)+1=12+1=13
legnth of ladder =13 feet
height=2x
2(6)=12
height=12 feet
base=x-1
6-1=5
legnth of ladder=13 feet
height=12 feet
base=5 feet