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3 years ago

Sition book

Mathematics

1 answer:

jenyasd209 [6]3 years ago

8 0

Answer:

a. The pattern is that each month, the number of trivia questions increases by 11.

b. Month 4 will have 44 questions, month 5 will have 52 questions, and month 6 will have 63 questions.

c. 8, 19, 30, 44, 52, 63, ...

Month - Questions

1 - 8

2 - 19

3 - 30

4 - 44

5 - 52

6 - 63

(There's no great way to format a table here, so you'll have to use your imagination!)

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I dont get this at all answer fast plz

Scrat [10]

Answer:

3960 Degrees

Step-by-step explanation:

There is a formula for this!

In this n=24 since there are 24 sides.

The formula is 180(n-2).

Hope this helped and please mark me as Brainliest if possible.

4 0

2 years ago

Simplify i^82 pls...thanks :)

Fofino [41]

To simplify i^82, divide 82 by. the answer is 20 with remainder 2

8 0

3 years ago

Read 2 more answers

Round to the nearest hundredth (Geometric Series problem)

WITCHER [35]

Answer:

15.98

Step-by-step explanation:

∑₁¹⁰ $8(\frac{1}{4} )^{n-1}$

$=8[1+\frac{1}{4} +\frac{1}{16} + ........ +t_{10}]$

We have to use the formula of sum of a G.P. series with common ratio r < 1.

If the first term is a, the common ratio is r and the number of terms is n then the sum [a + ar + ar² + ar³ + ......... up to n terms] is given by

$[a \times\frac{1-r^{n} }{1-r}]$

$= 8[1 \times \frac{1-\frac{1}{2^{10} } }{1-\frac{1}{2} } ]$

$= 15.98$ (Answer)

4 0

3 years ago

Anybody can help?????

Vikentia [17]

The formula of an area of a circle:

$A=\pi r^2$

r - a radius

We have r = 14m. Substitute:

$A=\pi\cdot14^2=196\pi\ m^2$

If you want an approximate area, you can accept $\pi\approx3.14$

Then:

$A\approx196\cdot3.14=615.44\ m^2$

7 0

3 years ago

the standard addition algorithm below is being used to add three two-digit numbers 4z + 27 + x 5 equals y 14. If x, y, and z eac

Studentka2010 [4]

For the units positions of all numbers we have:
$z+7+5=4 \\ z+12=4$
From this we can conclude that total sum of these three numbers is 14. Number 1 we carry to next step. So we have:
$z+12=14 \\ z=2$

For the tens positions of all numbers we have:
$4+2+x+1=1 \\ 7+x=1$
The extra number 1 on left side comes from the carry from last step. Similar to ones position we know that total sum is 11.
$7+x=11 \\ x=4$

Now we insert x and z to find out y:
$42+27+45=y14 \\ 114=y14 \\ y=1$

Now we need to find out the product of these three numbers:
$x*y*z=4*1*2=8$

3 0

3 years ago