Y+12=-50 y=-62
To solve
Subtract 12 from each side of the equation
y=-62
Y=-62
For this case we must find the product of the following expressions:
\frac {3x} {x + 1} * \frac {x} {x-7}
So:
\frac {3x ^ 2} {x ^ 2-7x + x-7} =\\\frac {3x ^ 2} {x ^ 2-6x-7}
So, we have to:
\frac {3x} {x + 1} * \frac {x} {x-7} = \frac {3x ^ 2} {x ^ 2-6x-7}
Answer:
\frac {3x ^ 2} {x ^ 2-6x-7}
Step-by-step explanation:
Answer:
There's a proportion relationship between number of shell and their cost
Step-by-step explanation:
The graph is not given.
However, I've added the appropriate graph as an attachment.
From this, point....
I'll show that the cost and number of shells as given in the question are proportional.
Represent cost with y and number of shells with x
x = 2 when y = 0.8
x = 3 when y = 1.2
x = 4 when y = 1.6
Divide each value of y by x to get the constant of proportion (r).
r = y/x
r = 0.8/2 = 0.4
r = 1.2/3 = 0.4
r = 1.6/4 = 0.4
Notice that the values of r remain constant.
Hence, there's a proportion relationship between both
And what this rate represent is that:.the cost of shell changes at a constant rate when the number of shell is changes.
What is the mode for the data set? 59, 57, 56, 50, 58, 51, 54, 59, 55, 52, 53.
zavuch27 [327]
Mode means the number that appears most often in the data. Below I provided a tally of how many each of the numbers appear
59: twice
57: once
56: once
50: once
58: once
51: once
54: once
59: once
55: once
52; once
53: once
As you can see 59 appears the most often, being listed twice in the data set, and is therefore the mode
Hope this helped!