6/2*3 / 3(3)
First simplify the numerator: 6/2*3 = 3*3 = 9
Next simplify the denominator: 3(3) = 3*3 = 9
So you have 9/9, which equals 1.
The 3rd answer is correct.
Answer:
<h2>(0.3, -18.45).</h2>
Step-by-step explanation:
We need to recur to the extreme value theorem, which states: "If a function is continuous on a closed interval, then that function has a maximum and a minimum inside that interval".
Basically, as the theorem states, if a dunction is continuous, then it has maxium or minium.
In this case, we have a quadratic function, which is a parabola. An important characteristic of parabolas is that they have a maximum or a minium, but they don't have both. When the quadratic term of the fuction is positive, then it has a minium at its vertex. When the quadratic term of the function is negative, then it has a maximum at its vertex.
So, the given function is
, where the quadratic term is positive, so the functions has a minimum at
, where
and
, let's find that point
<h3>

</h3><h3>

</h3><h3 /><h3>Therefore, the minium of the function is at (0.3, -18.45).</h3>
100/13.5 + 24 = 31.41 approximitely
Answer:
a. 60%
b. 37%
c. 3%
Step-by-step explanation:
a. 72/ 120 then multiply by 100
b. 120- 72 + 4 = 44/ 120 x 100
c. 4/120 x 100
Given
w = 3y-2n w = 19 and n = 7
thus
19= 3y-2*7
19 =3y-14
33 = 3y
y = 11