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Stolb23 [73]
3 years ago
10

What is the solution to the system of equations below?

Mathematics
1 answer:
zlopas [31]3 years ago
6 0

Answer:

x = 3 and y=4

Step-by-step explanation:

apply elimination method in simultaneous equations

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At a dinner, the meal cost $22 and a sales tax of $1.87 was added to the bill. How much would the sales tax be on a $66 meal? An
quester [9]

Answer:

$5.61

Step-by-step explanation:

we know that

At a dinner, the meal cost $22 and a sales tax of $1.87 was added to the bill.

so

using a proportion

Find out how much would the sales tax be on a $66 meal

Let

x ----> the amount of sales tax on a $66 meal

\frac{22}{1.87}=\frac{66}{x}\\\\x=1.87(66)/22\\\\x=1.87(3)\\\\x=\$5.61

6 0
4 years ago
8.4 divided by 0.02 equals
MatroZZZ [7]

Answer:

the answer to your problem would be 420

8 0
3 years ago
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What is the answer for this question?
Aloiza [94]

Answer:

Well I can give you advice, so first ask yourself if you actually read the whole problem. Did you? okay then make sure you've looked closely at the data table. What does it mean? Then try to put it all together and see if you can figure it out yourself, and if your stuck then I would suggest coming back.

Step-by-step explanation:

8 0
3 years ago
A house has decreased in value by 34% since it was purchased. If the current value is $165,000, what was the value when it was p
VashaNatasha [74]

Answer:

Step-by-step explanation:

Solution

Let the original price = x

x - 34/100 x = 165,000

0.65x = 165 000                            Divide by 0.65

0.65x/0.65 = 165000/0.65           Combine

Answer

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3 0
2 years ago
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A Geiger counter counts the number of alpha particles from radioactive material. Over a long period of time, an average of 14 pa
UkoKoshka [18]

Answer:

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Over a long period of time, an average of 14 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period.

Each minute has 60 seconds, so \mu = \frac{14}{60} = 0.2333

Either no particle arrives, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.2333}*(0.2333)^{0}}{(0)!} = 0.7919

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7919 = 0.2081

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

8 0
4 years ago
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