Answer: y = 1x + -4
Equation of a straight line:
y = mx + b ------(i)
Step by Step Solution:
Step 1: Calculating Slope (m).
m = y2-y1 /x2-x1
m = 3--1 /7-3
m = 4/4
m = 1
Now putting value of m in equation (i)
y = 1x + b -----(ii)
Step 2: Calculating Y-intercept (b).
Lets choose the first point, (3,-1) for calculating y-intercept:
y = mx + b
-1 = 1(3) + b
-1 = 3 + b
-4 = b
b = -4
Now putting value of b in equation (ii)
y = 1x + -4
Answer:
C ) y + 3 = 1/4 ( x + 4 )
Explanation:
Given that you did not include the "given line", I can help you by explaning how to solve this kind of problems, step by step.
The procedure is based of the property of perpendicular lines: the product of the slopes of perpedicular lines is negative 1.
If you call m1, the slope of a line and m2 the slope of a perpendicular line, then:
m1 * m2 = - 1, and you can solve for either m1 or m2:
m1 = - (1 / m2)
m2 = - (1 / m1).
With that this is the procedure:
1) find the slope of the "given line". Name it m1.
2) find the slope of the perpendicular line:
m2 = - (1 / m1).
3) Use the equation of the line with the point (x1,y1) and slope m2
y - y1
-------- = m2
x - x1
4) In this case the point is (-4, - 3)=> x1 = - 4, y1 = - 3
=>
y - (-3)
---------= m2
x - (-4)
=> y + 3 = m2 * (x + 4)
=> y = m2*x + m2 * 4 - 3
Which is the point-slope form. You only have to replace m2 with the slope value of the perpendicular line, which I already explained that you find as m2 = (-1/m1).
Taking that the other line has m1 = - 4 so m2 = 1/4
y = (1/4)x + (1/4) * 4 - 3
y = (1/4) (x +4) - 3
y + 3 = (1/4) (x + 4) and answer is:
C ) y + 3 = 1/4 ( x + 4 )
Answer:
B -11
Step-by-step explanation:
2x-3=5x+30
or,2x-5x=30+3
or,-3x=33
x=-11
I have the scatterplot in front of me, and what the question is asking is what is the probability of the dot chosen being in any of the three categories. They only leave out three dots, so the probability is 17/20 or 85%.
