The function is in polar coordinates.
When this is the case, to pass to rectagular (cartesian) coordinates you use:
x = r cos(theta)
y = r sin(theta)
Then,
x = [2cos(theta) + 2sin(theta)]cos(theta) =
= 2 [cos(theta)]^2 + 2sin(theta)cos(theta) = 2 [cos(theta)]^2 + sin(2theta)
y = [2cos(theta) + 2sin(theta)]sin(theta) =
= 2 cos(theta)sin(theta) + 2[sin(theta)]^2 = sin(2theta) + 2[sin(theta)]^2
Hey!
So the first thing we can notice is that we are given the equation of the line parallel to the one we need to find. Two parallel lines always have the same slope. We can tell by looking at the equation that the slope of the line that we have been given is 1 and since the lines are parallel the slope of the line we need to find is also 1.
Knowing this and a point that the line passes through, we can find the y-intercept or b:
y = mx + b
4 = 1(1) + b
4 = 1 + b
3 = b
Since we know that the y-intercept is 3, we can plug this back into the slope intercept form equation along with the slope to get our equation:
y = x + 3
YEAH OFC SHAWTY!
- so for A its -4^11 because if the powers have the same base and they are being multiplied you add the powers
- For B its the same idea, they have the same base, and are being multiplied so you add the powers- 13^9
- For C its similar, you have the same base, but since its Dividing, you subtract the powers. So, 9^5
- for D you pretend like the denominator has a power of 1 and subtract. So its -24^5-24^1 which hopefully puts it into perspective of being -24^4 becuase we subtracted the powers
I cant do 2 right now, but i will in a minute
<u>And for 3 his mistake is that they arent the same bases so he cant add the powers, he should have converted them to the same base first. </u>
4x+1=6x-2
4x+3=6
3=2x
3/2=2x/2, because you have to divide 2 from both sides
X=3/2
Answer: um, you mean 10 + 122=132, the second one is n>4 if you want step by step look below:
Let's solve your inequality step-by-step.
3n>12
Step 1: Divide both sides by 3.
3n/3 > 12/3
n>4
You can use a numberline too.
