Vertex is directly in middle of directix and focus
distance from 8 to -8 is 16
16/2=8
so 8 below focus (since 8>-8) is the point (0,0
vertex is (0,0)
nice
it opens up because focus is above directix
also it goes up down so
4p(y-k)=(x-h)^2
(h,k) is veretx
we got that (h,k) is (0,0)
and p is distance from vertex to focus which is 8
so
4(8)(y-0)=(x-0)^2
32y=x^2
y=(1/32)x^2
Answer:
35
Step-by-step explanation:
<span>85 x 63 = 5355
hope it helps
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Answer: 3/8
Step-by-step explanation:
It’s the answer :>
To solve this, we have to find the volume of the cylinder first. The formula to be used is
![V = \pi r^{2} h](https://tex.z-dn.net/?f=V%20%3D%20%20%5Cpi%20%20r%5E%7B2%7D%20h)
Given:V= ?r= 6cmh= 10cm
Solution:
![V = \pi r^{2} h](https://tex.z-dn.net/?f=V%20%3D%20%20%5Cpi%20%20r%5E%7B2%7D%20h)
V= (3.14)(6cm)
![^{2}](https://tex.z-dn.net/?f=%5E%7B2%7D%20)
x 10cmV= (3.14)(
![36cm^{2}](https://tex.z-dn.net/?f=36cm%5E%7B2%7D%20)
) x 10cmV= (
![113.04cm^{2}](https://tex.z-dn.net/?f=%20113.04cm%5E%7B2%7D%20)
) x 10cmV= 1130.4cm^3
Finding the volume of the cylinder, we can now solve what the weight of the oil is. Using the formula of density, Density = mass/volume, we can derive a formula to get the weight.
Given:Density = 0.857 gm/cm^3Volume = 1130.4 cm^3
Solution:weight = density x volumew= (0.857 gm/cm^3) (1130.4cm^3)w= 968.7528 gm
The weight of the oil is 968.75 gm.