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Anon25 [30]
4 years ago
6

An apartment building has a land value set at $30,000. The investor recently bought the property for $150,000. Assuming an econo

mic life for the improvement to be 35 years, using the straight-line approach, what would be the value of the property after 14 years?
Mathematics
1 answer:
allsm [11]4 years ago
8 0

Answer:

$102,000

Step-by-step explanation:

Given:

Set land value = $30,000

Buying cost of the property = $150,000

Now,

The Improvement Value = Buying cost - Land value

or

The Improvement Value = $150,000 - $30,000 = $120,000

Now,

Depreciation per year = \frac{\textup{Improvement value}}{\textup{Economic life}}

or

Depreciation per year = \frac{\textup{120,000}}{\textup{35}}

or

Depreciation per year = $3,428.57

Therefore,

The depreciated over 14 years = $3,428.57 × 14 yrs = $48,000

Hence,

the value of property after 14 years will be

= $150,000 - $48,000

= $102,000

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4 years ago
Find the interest rate needed for the sinking fund to reach the required amount. Assume that the compounding period is the same
Maslowich

Answer:

so rate is 4.72 %

Step-by-step explanation:

Given data

time (t) = 5 year  = 5×4 = 20 quarterly

amount = $27456

principal = $1225

to find out

interest rate (r)

solution

we use here amount formula that is

amount = principal ((1+r)^{t} -1 ) / r      .....................1

put all value principal , amount and time in equation 1 and we get rate

rate is r/4 because it is quarterly payment

amount = principal ((1+r/4)^{t} -1 ) / r/4

27456 = 1225 ((1+r/4)^{20} -1 ) / r/4

((1+r/4)^{20} -1 ) / r/4  = 27456/ 1225

((1+r)^{20} -1 ) / r  = 27456/ (1225 × 4)

((1+r)^{20} -1 ) = r 27456/ (1225 × 4)

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5 0
3 years ago
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Which ordered pair is a solution to this system of equations?y = x2 – 3x + 3 y = 3x – 6
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Assuming the first term in the first equation is actually x^2, then the ordered pair is C. (3, 3).
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A rectangular stirp of asphalt paving is 5 meters longer than it is wide. its area is 300 square meters. find the length and wid
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Moreover, we know that the length is 5 meters longer than the width:
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We have a system of 2 equations in 2 unknown variables, L and W. If we substitute the second equation into the first one, we get
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which has two solutions: W=-20 and W=15. We can discard the negative solution since it does not have physical meaning, and now we can substitute the value of W into the second equation to find L:
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<span>Therefore, the rectangle has width 15 meters and length 20 meters.</span>
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