Would depend on how many other students are in the class/school.
The lateral area of the prism is given by:
LA=[area of the two triangles]+[area of the lateral rectangles]
hypotenuse of the triangle will be given by Pythagorean:
c^2=a^2+b^2
c^2=6^2+4^2
c^2=52
c=sqrt52
c=7.211'
thus the lateral area will be:
L.A=2[1/2*4*6]+[6*8]+[8*7.211]
L.A=24+48+57.69
L.A=129.69 in^2
The total are will be given by:
T.A=L.A+base area
base area=length*width
=4*8
=32 in^2
thus;
T.A=32+129.69
T.A=161.69 in^2
Answer:
(-3, 4)
It doesn't show any coordinates so I assume that the origin is where the x and y axes intercept
Answer:
35/3 yd
Step-by-step explanation:
first convert the hypotenuse into 37/3, then you can write (37/3)^2-(4)^2=a^2. solve to get 35/3
