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dlinn [17]
3 years ago
9

Find the measure of the angle.

Mathematics
2 answers:
4vir4ik [10]3 years ago
4 0

Answer:

24°

Step-by-step explanation:

Check file attatched! :D

(sorry for sloppy/etc writing haha, it's hard with a mouse lol)

Travka [436]3 years ago
3 0

\\ \sf\longmapsto

Now

\\ \sf\longmapsto m

\\ \sf\longmapsto m

\\ \sf\longmapsto m

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8 0
2 years ago
The position of an object along a vertical line is given by s(t) = −t3 + 3t2 + 7t + 4, where s is measured in feet and t is meas
saw5 [17]

Answer:

The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

Step-by-step explanation:

Given : The position of an object along a vertical line is given by s(t) = -t^3+3t^2+7t +4, where s is measured in feet and t is measured in seconds.

To find : What is the maximum velocity of the object in the time interval [0, 4]?

Solution :

The velocity is rate of change of distance w.r.t time.

Distance in terms of t is given by,

s(t) = -t^3+3t^2+7t +4

Derivate w.r.t. time,

v(t)=s'(t) = -3t^2+6t+7

It is a quadratic function so its maximum is at vertex of the function.

The x point of the function is given by,

x=-\frac{b}{2a}

Where, a=-3, b=6 and c=7

t=-\frac{6}{2(-3)}

t=-\frac{6}{-6}

t=1

As 1 lie between interval [0,4]

Substitute t=1 in the function,

v(t)= -3(1)^2+6(1)+7

v(t)= -3+6+7

v(1)=10

Th maximum velocity is 10 ft/s.

Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

8 0
3 years ago
Read 2 more answers
-2/7 - (-4/3) -1/3 what is the answer
seraphim [82]
You have to first make like terms 

-\frac{2}{7} -(-  \frac{4}{3})-  \frac{1}{3} 

**you want the denominator to be 21 

\frac{-6+28-7}{21} =  \frac{15}{21}= \frac{5}{7}
3 0
3 years ago
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