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Gre4nikov [31]
3 years ago
10

a trader always 12% discount and sold a fan at a loss of rs 16 if he had sold it at 10% discount he will have gain rupees 20 for

what price did he purchased the fan​
Mathematics
2 answers:
Levart [38]3 years ago
7 0

Answer:

You’re saying that the trader sold something at a small discount and lost money on the deal. But if he’d given a bigger discount, and so sold it at a lower price, he’d have made a profit. Sorry, I just don’t see how that is possible!

sergejj [24]3 years ago
3 0

Answer:

profit = 30number is the answer of that question answer sapai

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The box plots show the weights, in pounds, of the dogs in two different animal shelters. Weights of Dogs in Shelter A 2 box plot
katovenus [111]

Answer:

1) The median weight for shelter A is greater than that for shelter B.

True, the median weight for shelter A is 21 pounds as compared to the 18 pounds median weight for shelter B.

4) The data for shelter B are a symmetric data set.

True, the median is exactly 2 pounds away from each quartile which means it is symmetric.

5) The interquartile range of shelter A is greater than the interquartile range of shelter B.

True, the interquartile range of shelter A is 11 pounds as compared to the 4 pounds interquartile range of shelter B.

Step-by-step explanation:

We are given two box-plots, a box plot basically shows 5 statistical characteristics of a data set and they are  

1. minimum value  

2. Lower quartile  

3. Median value  

4. Upper quartile  

5. Maximum value  

Box-plot of dogs in shelter A:

The whiskers range from 8 to 30

Which means that the range is = 30 - 8 = 22

The box ranges from 17 to 28

Which means that the interquartile range is = 28 - 17 = 11

21 - 17 = 4

28 - 21 = 9

The median is not equal distance away from each quartile which means that the box-plot is not symmetric.

A line divides the box at 21

Which means that the median is = 21

Box-plot of dogs in shelter B:

The whiskers range from 10 to 28

Which means that the range is = 28 - 10 = 20

The box ranges from 16 to 20

Which means that the interquartile range is = 20 - 16 = 4

18 - 16 = 2

20 - 18 = 2

The median is exactly 2 pounds away from each quartile which means it is symmetric.

A line divides the box at 18

Which means that the median is = 18

Which is true of the data in the box plots?

1) The median weight for shelter A is greater than that for shelter B.

True, the median weight for shelter A is 21 pounds as compared to the 18 pounds median weight for shelter B.

2) The median weight for shelter B is greater than that for shelter A.

False

3) The data for shelter A are a symmetric data set.

False

4) The data for shelter B are a symmetric data set.

True

5) The interquartile range of shelter A is greater than the interquartile range of shelter B.

True, the interquartile range of shelter A is 11 pounds as compared to the 4 pounds interquartile range of shelter B.

5 0
4 years ago
A construction worker is looking at blueprints drawn to a 1/20 scale and notices that a wall is 0.5 feet by 0.25 feet. He claims
Gnoma [55]

Answer:

incorrect

Step-by-step explanation:

we are finding area which is squared, or we can put it in an equation, (0.5*20)*(0.25*20) or 0.5*0.25*20^2 which equals 50      but (0.5*0.25)*20 only equals 2.5    therefor he is incorrect and the correct answer would be 20^2 or 400 times the area.

hope this helps :)

5 0
3 years ago
Is the relationship shown by the data linear? If so, model the data with an equation.
zhenek [66]

Answer:

Therefore the equation of the line through ( -7 , 5 ) and ( -5 , 9) is

Linear Relationship i.e y-5=2(x+7)

Step-by-step explanation:

Given:

Let,

point A( x₁ , y₁) ≡ ( -7, 5 )  

point B( x₂ , y₂) ≡ (-5, 9)  

To Find:

Equation of Line AB =?

Solution:

Equation of a line passing through Two points A( x₁ , y₁) and B( x₂ , y₂)is given by the formula

(y - y_{1} )=(\frac{y_{2}-y_{1} }{x_{2}-x_{1} })\times(x-x_{1}) \\

Substituting the given values in a above equation we get

(y-(5))=(\frac{9-(5)}{-5--7})\times (x--7)\\ \\(y-5)=\frac{4}{2}(x+7)\\\\y-5=2(x+7)...............\textrm{which is the required equation of the line AB}

Therefore the equation of the line through ( -7 , 5 ) and ( -5 , 9 ) is

Linear Relationship i.e y-5=2(x+7)

4 0
3 years ago
Use properties of equality to simplify each of the following expressions so that you can simplify them in your head. Identify th
Salsk061 [2.6K]
Properties of equality have nothing to do with it. The associative and commutative properties of multiplication are used (along with the distributive property and the fact of arithmetic: 9 = 10 - 1).

All of these problems make use of the strategy, "look at what you have before you start work."


1. = (4·5)·(-3) = 20·(-3) = -60 . . . . if you know factors of 60, you can do this any way you like. It is convenient to ignore the sign until the final result.

2. = (2.25·4)·23 = 9·23 = 23·10 -23 = 230 -23 = 207 . . . . multiplication by 4 can clear the fraction in 2 1/4, so we choose to do that first. Multiplication by 9 can be done with a subtraction that is often easier than using ×9 facts.

4. = (2·5)·12·(-1) = 10·12·(-1) = (-1)·120 = -120 . . . . multiplying by 10 is about the easiest, so it is convenient to identify the factors of 10 and use them first. Again, it is convenient to ignore the sign until the end.

5. = 0 . . . . when a factor is zero, the product is zero
4 0
4 years ago
Which choice is equivalent to the expression below? √-49<br><br>btw its 7i
Nastasia [14]

Answer:

7

Step-by-step explanation:

3 0
3 years ago
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