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tankabanditka [31]

3 years ago

10

On a 30-question test, Janice answered four-fifths of the questions correctly. Which of the following is the number of questions

she answered correctly?
(1) 24
(2) 25
(3) 26
(4) 28

1 answer:

ki77a [65]3 years ago

8 0

Hi!

Your answer should be: (4) 28.

Hope this helps!

<em>Yours truly,</em>

<h2><em>~~~PicklePoppers~~~</em></h2>

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Given M is the midpoint ABA. The coordinate of A are (-4,2) and the cordinates of M are (1,1). Find the coordinate of B. Choose

4vir4ik [10]

Answer:

The coordinate of B is (6,0)

Step-by-step explanation:

Given;

coordinate of A = (-4,2) = (x₁, y₁)

coordinate of M = (1,1)

let coordinate of B = (x₂, y₂)

Mid-point is given by;

$M = \frac{X_1 + X_2}{2} , \frac{Y_1 + Y_2}{2}\\\\M= (1,1)\\\\1,1 =\frac{X_1 + X_2}{2} , \frac{Y_1 + Y_2}{2}\\\\ \frac{X_1 + X_2}{2} = 1 ----equation (1)\\\\\frac{Y_1 + Y_2}{2} = 1 -----equation(2)\\\\Solving \ equation(1)\\\\\frac{-4+ X_2}{2} = 1\\\\-4+ X_2 = 2\\\\X_2 = 2+4\\\\X_2 = 6\\\\Solving \ equation(2)\\\\\frac{Y_1 + Y_2}{2} = 1\\\\\frac{2+ Y_2}{2} = 1\\\\2+Y_2 = 2\\\\Y_2 = 2-2\\\\Y_2 = 0\\\\B = (X_2, \ Y_2)\\\\B = (6, \ 0)$

Therefore, the coordinate of B is (6,0)

5 0

3 years ago

Which equation represents the line that passes through (–6, 7) and (–3, 6)? y = –y equals negative startfraction one-third endfr

egoroff_w [7]

The equation represents the line that passes through (–6, 7) and (–3, 6) $\rm y=\dfrac{-1}{3}x+5$ .

<h3>What is the slope of the equation?</h3>

For all lines in slope y-intercept form, it would be very simple to just find the answer by finding yourself the slope and y-intercept of the line in question.

The slope of the line is;

$\rm m = \dfrac{y_2-y_1}{x_2-x_1}\\\\m =\dfrac{7-6}{-6-(-3)}\\\\m = \dfrac{1}{-3}$

The equation represents the line that passes through (–6, 7) and (–3, 6) is;

$\rm y=\dfrac{-1}{3}x+b\\\\6=\dfrac{-1}{3}(-3)+b\\\\6=1+b\\\\b = 6-1\\\\b=5$

The required line of the equation is;

$\rm y =mx+c\\\\y=\dfrac{-1}{3}x+5$

Hence, the equation represents the line that passes through (–6, 7) and (–3, 6) $\rm y=\dfrac{-1}{3}x+5$ .

To know more about the equation of line click the link given below.

brainly.com/question/8955867

3 0

2 years ago

Need help with math ASAP (Please)

Scrat [10]

First you plot in the y-intercept of the equation. To find the y-intercept, substitute 0 into x. -3m will cancel our giving you y=5. x=0, y=5, the first ordered pair is (0,5). Now after you plot in the y-intercept, use your slope, which is -3, to graph the points of the equation. Starting from (0,5), move down 3 spaces on the y-axis (because it’s -3) and you’ll end up at (0,2). Next move over 1 ( all slopes with just a whole number moves on the x-axis 1 since the whole number divided by 1 doesn’t change the slope number) to the right because it’s a negative linear equation so it’ll go downward. After moving right, you’ll get (1,2). Do a couple more points starting from (1,2) then the 3rd point ABD and so on to get 3 or more points to be able to draw a linear line.

7 0

3 years ago

Read 2 more answers

Diego‘s mother is twice as old as he is. She is also as old as the sum of the ages of Diego and both of his younger twin brother

Pavel [41]

Diego's age is 22
And his mother's age is 42

5 0

3 years ago

For the composite function, identify an inside function and an outside function and write the derivative with respect to x of th

alexira [117]

Answer:

The inner function is $h(x)=4x^2 + 8$ and the outer function is $g(x)=3x^5$ .

The derivative of the function is $\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4$ .

Step-by-step explanation:

A composite function can be written as $g(h(x))$ , where $h$ and $g$ are basic functions.

For the function $f(x)=3(4x^2+8)^5$ .

The inner function is the part we evaluate first. Frequently, we can identify the correct expression because it will appear within a grouping symbol one or more times in our composed function.

Here, we have $4x^2+8$ inside parentheses. So $h(x)=4x^2 + 8$ is the inner function and the outer function is $g(x)=3x^5$ .

The chain rule says:

$\frac{d}{dx}[f(g(x))]=f'(g(x))g'(x)$

It tells us how to differentiate composite functions.

The function $f(x)=3(4x^2+8)^5$ is the composition, $g(h(x))$ , of

outside function: $g(x)=3x^5$

inside function: $h(x)=4x^2 + 8$

The derivative of this is computed as

$\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=3\frac{d}{dx}\left(\left(4x^2+8\right)^5\right)\\\\\mathrm{Apply\:the\:chain\:rule}:\quad \frac{df\left(u\right)}{dx}=\frac{df}{du}\cdot \frac{du}{dx}\\f=u^5,\:\:u=\left(4x^2+8\right)\\\\3\frac{d}{du}\left(u^5\right)\frac{d}{dx}\left(4x^2+8\right)\\\\3\cdot \:5\left(4x^2+8\right)^4\cdot \:8x\\\\120x\left(4x^2+8\right)^4$

The derivative of the function is $\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4$ .

3 0

3 years ago