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lutik1710 [3]
3 years ago
13

3

Mathematics
1 answer:
zvonat [6]3 years ago
6 0

Answer:

Dont understands the lay out of this question.

Step-by-step explanation:

Please Explain in details.

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Helppppppppppppppppppppppppppppp​
juin [17]

Answer:

jvghbjjjj

Step-by-step explanation:

helping is caring

5 0
3 years ago
Read 2 more answers
nathan smiled at 50 people one day and recorded that 36 people smiled back at him.Based on his observations how many people shou
Olegator [25]

Given :

Nathan smiled at 50 people one day and recorded that 36 people smiled back at him.

To Find :

How many people should Nathan expect to return a smile if he smiles at 650 people over a period of time.

Solution :

Ratio of people smiled by total number of people is :

R = \dfrac{36}{50}

Now, it is given that we have to use the given conditions.

Therefore, ratio will be same :

\dfrac{s}{650}=\dfrac{36}{50}\\\\s = \dfrac{36}{50}\times 650\\\\s = 468

Therefore, number of smiles Nathan expect to return is 468.

4 0
3 years ago
WILL GIVE BRAINLIEST<br><br> just need answer:)
dedylja [7]
I think its b im sure
4 0
3 years ago
Read 2 more answers
Can someone please help me with this question.
rusak2 [61]
25x25+20x25+20x15+15x25=1800 the answer is D.
5 0
4 years ago
In previous​ tests, baseballs were dropped 24 feet onto a concrete​ surface, and they bounced an average of 92.82 inches. In a t
goblinko [34]

Answer:

There is sufficient evidence to support the claim that the new balls have bounce heights with a mean different from 92.8292.82 inches, and it appears that the new baseballs are​ different

Step-by-step explanation:

Given that in previous​ tests, baseballs were dropped 24 feet onto a concrete​ surface, and they bounced an average of 92.82 inches

But new balls showed mean of 92.6 inches with s = 1.72 inches

Sample size = 23

Since sample size is less than 30 and population std deviation is not know we use t test

H_0: \bar x = 92.82\\H_a: \bar x \neq 92.82

(Two tailed test at 5% significance level)

Mean difference = 92.6-92.82=-1.22

Std error of sample mean = s/sqrt n = \frac{1.72}{\sqrt{23} } \\=0.3586

Test statistic t = mean diff/std error = -3.402

df = 23-1 =22

p value = 0.002559

since p value <5% we reject H0

There is sufficient evidence to support the claim that the new balls have bounce heights with a mean different from 92.8292.82 inches, and it appears that the new baseballs are​ different

3 0
3 years ago
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