Ask question

Ask question

All categories

2 years ago

12

Judd is 3 years older than Jordan. Jordan is 6 years younger than Chris. Write an algebraic expression for the sum of their ages

.

1 answer:

Cloud [144]2 years ago

6 0

Answer:

تيتلتبنبزلمينبووبصحثنل

You might be interested in

5. A 12 sided diɛ is rolled. The set of equally

professor190 [17]

Answer:

Step-by-step explanation:

5 0

3 years ago

Why should you generally expect some error when estimating a parameter? (for example, a population? mean) by a statistic? (for e

nexus9112 [7]

This is called as sampling error or sampling variability. Sampling error is the variability that happens because the value of a sample statistic varies from sample to sample. Sampling error is acquired when a population is estimated from a subset, or sample.

8 0

3 years ago

Al factorizar el trinomio cuadrado perfecto, obtenemos el siguiente resultado: (que no se como resolver) xd algun pro que sepa r

PolarNik [594]

Answer:

$\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2$

Step-by-step explanation:

<u>Trinomio Cuadrado Perfecto</u>

El producto notable llamado cuadrado de un binomio se expresa como:

$(a-b)^2=a^2-2ab+b^2$

Si se tiene un trinomio, es posible convertirlo en un cuadrado perfecto si cumple con las condiciones impuestas en la fórmula:

* El primer término es un cuadrado perfecto

* El último término es un cuadrado perfecto

* El segundo término es el doble del proudcto de los dos términos del binomio.

Tenemos la expresión:

$\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8$

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

$\displaystyle a=\sqrt{\frac{100}{81}m^8p^{12}q^{16}z^2}$

$\displaystyle a=\frac{10}{9}m^4p^{6}q^{8}z$

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

$\displaystyle b=\sqrt{\frac{1}{49}m^2p^2z^8$

$\displaystyle b=\frac{1}{7}mpz^4$

Nos cercioramos de que el término central es 2ab:

$\displaystyle 2ab=2\frac{10}{9}m^4p^{6}q^{8}z\frac{1}{7}mpz^4$

Operando:

$\displaystyle 2ab=\frac{20}{63}m^5p^7q^8z^5$

Una vez verificado, ahora podemos decir que:

$\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2$

5 0

2 years ago

SOLVE THIS PROBLEM ASAP PLS

deff fn [24]

Answer:

See attached

Step-by-step explanation:

-> Also see attached

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

7 0

3 years ago

trey is selling candy bars to raise money for his basketball team. the team receives $1.25 for each candy . he has already sold

zlopas [31]

Answer:

He has earned $31.25 for his basketball team.

Step-by-step explanation:

25 * 1.25 = 31.25

8 0

3 years ago

Read 2 more answers