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olchik [2.2K]
2 years ago
15

What error was made? -4(6 - b) = 4 -24 - 4b = 4 -4b = 28 b = -7

Mathematics
1 answer:
lisov135 [29]2 years ago
3 0

Answer:

step 2; a negative times a negative = a positive.

Step-by-step explanation:

-4(6-b)=4

<u>-24 </u><u>+</u><u>4b=4</u>

4b=28

b=7

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20 POINTS PLS HALP!!!
Morgarella [4.7K]

Answer:

number of people / land area = population density

57,714 / 836,109 ≈ 0.07 people/mi^2

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3 years ago
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What is the solution to the inequality 2n+5| &gt; 1?
hodyreva [135]

Answer:

n < - 3 or n > - 2

Step-by-step explanation:

Inequalities of the type | x | > a , have solutions of the form

x < - a or x > a

Then

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Solve both inequalities

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3 years ago
Joe is making a recipe that calls for 3/4 tsp of cinnamon. His only measuring spoon holds 1/8 teaspoon. How many times will he n
SashulF [63]
6 times because you find the common denominator which is 8 so 3/4 is 6/8. He needs to fill his cup 6 times.

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3 years ago
A system of equations is graphed on the coordinate plane.
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no solutions

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find the equation of the circle where (-9,4),(-2,5),(-8,-3),(-1,-2) are the vertices of an inscribed square.
solniwko [45]
Check the picture below, so, that'd be the square inscribed in the circle.

so... hmm the diagonals for the square are the diameter of the circle, and keep in mind that the radius of a circle is half the diameter, so let's find the diameter.

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that means the radius r = 5.

now, what's the center?  well, the Midpoint of the diagonals, is really the center of the circle, let's check,

\bf \textit{middle point of 2 points}\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;&({{ -2}}\quad ,&{{ 5}})\quad &#10;%  (c,d)&#10;&({{ -8}}\quad ,&{{ -3}})&#10;\end{array}\qquad &#10;\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)&#10;\\\\\\&#10;\left( \cfrac{-8-2}{2}~,~\cfrac{-3+5}{2} \right)\implies (-5~,~1)

so, now we know the center coordinates and the radius, let's plug them in,

\bf \textit{equation of a circle}\\\\ &#10;(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2&#10;\qquad &#10;\begin{array}{lllll}&#10;center\ (&{{ h}},&{{ k}})\qquad &#10;radius=&{{ r}}\\&#10;&-5&1&5&#10;\end{array}&#10;\\\\\\\&#10;[x-(-5)]^2-[y-1]^2=5^2\implies (x+5)^2-(y-1)^2=25

8 0
3 years ago
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