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olchik [2.2K]
3 years ago
15

What error was made? -4(6 - b) = 4 -24 - 4b = 4 -4b = 28 b = -7

Mathematics
1 answer:
lisov135 [29]3 years ago
3 0

Answer:

step 2; a negative times a negative = a positive.

Step-by-step explanation:

-4(6-b)=4

<u>-24 </u><u>+</u><u>4b=4</u>

4b=28

b=7

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Luba_88 [7]

Answer:

I mean 6

Step-by-step explanation:

That is the answere to you question.

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3 years ago
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Triphasil-28 birth control tablets are taken sequentially, 1 tablet per day for 28 days, with the tablets containing the followi
bazaltina [42]

Answer:

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

Step-by-step explanation:

The total milligrams of levonorgestrel is:

L = L_{1} + L_{2} + L_{3}

In which L_{1}, L_{2} and L_{3} are the number of miligrams of levonorgestrel taken in each phase.

The total milligrams of ethinyl estradiol is:

E = E_{1} + E_{2} + E_{3}

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We can solve this by phase.

Phase 1: 6 tablets, each containing 0.050 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

6*0.050mg = 0.30mg of levonorgestrel and 6*0.030mg = 0.18mg of ethinyl estradiol are taken.

So L_{1} = 0.30 and E_{1} = 0.18

Phase 2: 5 tablets, each containing 0.075 mg of levonorgestrel and 0.040 mg ethinyl estradiol

In this phase,

5*0.075mg = 0.375mg of levonorgestrel and 5*0.040mg = 0.20mg of ethinyl estradiol are taken.

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Phase 3: 10 tablets, each containing 0.125 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

10*0.125mg = 1.25mg of levonorgestrel and 10*0.030mg = 0.30mg of ethinyl estradiol are taken.

So L_{3} = 1.25 and E_{3} = 0.30

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L = L_{1} + L_{2} + L_{3} = 0.30 + 0.375 + 1.25 = 1.925

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E = E_{1} + E_{2} + E_{3} = 0.18 + 0.20 + 0.30 = 0.68

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3 years ago
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SashulF [63]
F(x) can be written as:
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Answer:

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