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Alborosie
3 years ago
8

Find the curvature of the parabola y=x^2 at A(1,1)

Mathematics
1 answer:
xxMikexx [17]3 years ago
6 0

Answer:

Step-by-step explanation:

The curvature of the curve y=f(x) is

y=f(x)=x^2\\\\y'=f'(x)=2x\\\\y''=f''(x)=2\\\\K(x)=courbure(in\  French)=\Bigg|\dfrac{y''(x)}{(1+y'(x)^2)^{\dfrac{3}{2} } }\Bigg|\\\\At\ A=(1,1),\\K(1)=\Bigg|\dfrac{2}{(1+2^2)^{\dfrac{3}{2} } }\Bigg|\\\\=\Bigg|\dfrac{2}{(5)^{\dfrac{3}{2} } }\Bigg|\\\\=\Bigg|\dfrac{2}{5*\sqrt{5} }\Bigg|\\\\=\Bigg|\dfrac{2*\sqrt{5}}{25 }\Bigg|\\\\\\\boxed{=\dfrac{2*\sqrt{5}}{25 }}\\\\

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Answer:

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Step-by-step explanation:

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4 0
3 years ago
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Step-by-step explanation:

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8 0
4 years ago
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What is the solution of the system of equations? y=2x+2 y=4x-2
Margarita [4]
{ y=2x+2
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——
Check solution:
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{6=6
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3 years ago
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