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son4ous [18]
3 years ago
11

Show ur work and check jt

Mathematics
1 answer:
Kazeer [188]3 years ago
7 0

Answer: 15

Step-by-step explanation:

m-5=10

m-5+5=10+5

m=15

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Read 2 more answers
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BARSIC [14]

Answer:

Part A) x = 11

B) length of BC =  x + 12 =  x + 12 = 11 + 12 =23

length of EF =  4x - 18 =  4(11) - 18 = 44 - 18 =26

length of AD =  3x - 18 =  3(11) - 4 = 33 - 4 =29

Step-by-step explanation:

Median of trapezium is m=\frac{base1+base2}{2}

In provided figure, base1 is x+12 and base2 is 3x-4

A) solve for value of x

calculate the median m=\frac{base1+base2}{2}

4x-18=\frac{x+12+3x-4}{2}

4x-18=\frac{4x+8}{2}

4x-18=2x+4

2x-18=4

2x = 18 + 4

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x = 11

B) To find the length of BC, AD and EF , put the value of x in equation of lines

length of BC =  x + 12 =  x + 12 = 11 + 12 =23

length of EF =  4x - 18 =  4(11) - 18 = 44 - 18 =26

length of AD =  3x - 4 =  3(11) - 4 = 33 - 4 =29

5 0
4 years ago
On a coordinate plane, 2 right triangles are shown. The first triangle has points A (negative 1, 3), B (negative 1, 1), C (3, 1)
Mars2501 [29]
The second and last answer choice
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3 years ago
7/7q+21= x /5q^2-45 then x=?​
anzhelika [568]

Answer:

x = 5q - 15

Step-by-step explanation:

\frac{7}{7q+21}=\frac{x}{5q^{2}-45}\\\\\frac{7}{7(q+3)}=\frac{x}{5 (q^{2} -9)}\\\\frac{1}{q+3}=\frac{x}{5*(q^{2}-3^{2})}\\\\\frac{1}{q+3}=\frac{x}{5(q+3)(q-3)}\\\\\frac{1}{q+3}*5*(q+3)(q-3)=x\\\\5(q-3)=x\\\\x= 5q-15

3 0
3 years ago
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