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3 years ago

Determine whether each expression in the table is equivalent to b(a+1)+a

Mathematics

1 answer:

victus00 [196]3 years ago

5 0

Answer:

• Algebraic expression is formed from variables and constants using

different operations.

• Expressions are made up of terms.

• A term is the product of factors. Factors may be numerical as well as

algebraic (literal).

• Coefficient is the numerical factor in a term. Sometimes, any factor

in a term is called the coefficient of the remaining part of the term.

• The terms having the same algebraic factors are called like terms.

• The terms having different algebraic factors are called unlike terms.

• Expression with one term is called a 'Monomial’.

• Expression with two unlike terms is called a 'Binomial’.

• Expression with three unlike terms is called a 'Trinomial’.

• In general, an expression with one or more than one term (with non-

negative integral exponents of the variables) is called a ‘Polynomial’.

• The sum (or difference) of two like terms is a like term with coefficient

equal to the sum (or difference) of coefficients of the two like terms.

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Find the absolute maximum and minimum values of the function below. f(x) = x3 − 9x2 + 3, − 3 2 ≤ x ≤ 12 Solution Since f is cont

Neko [114]

Answer:

There are an absolute minimum (x = 6) and an absolute maximum (x = 12).

Step-by-step explanation:

The correct statement is described below:

Find the absolute maximum and minimum values of the function below:

$f(x) = x^{3}-9\cdot x^{2}+ 3$ , $2 \leq x \leq 12$

Given that function is a polynomial, then we have the guarantee that function is continuous and differentiable and we can use First and Second Derivative Tests.

First, we obtain the first derivative of the function and equalize it to zero:

$f'(x) = 3\cdot x^{2}-18\cdot x$

$3\cdot x^{2}-18\cdot x = 0$

$3\cdot x \cdot (x-6) = 0$ (Eq. 1)

As we can see, only a solution is a valid critical value. That is: $x = 6$

Second, we determine the second derivative formula and evaluate it at the only critical point:

$f''(x) = 6\cdot x -18$ (Eq. 2)

x = 6

$f''(6) = 6\cdot (6)-18$

$f''(6) =18$ (Absolute minimum)

Third, we evaluate the function at each extreme of the given interval and the critical point as well:

x = 2

$f(2) = 2^{3}-9\cdot (2)^{2}+3$

$f(2) = -25$

x = 6

$f(6) = 6^{3}-9\cdot (6)^{2}+3$

$f(6) = -105$

x = 12

$f(12) = 12^{3}-9\cdot (12)^{2}+3$

$f(12) = 435$

There are an absolute minimum (x = 6) and an absolute maximum (x = 12).

6 0

3 years ago

Please help it’s due today

Semmy [17]

Answer:

1/2 is 4/8 and 5/8 is grater than it

Step-by-step explanation:

5 0

3 years ago

What would be the expression?

Gala2k [10]

6*6-(3*3)-(2*2) is the answer

7 0

3 years ago

Answer of a ²-10a+16-6b-b^2

german

$\quad a^2-10a+16-6b-b^2$

$=(a^2-10a)-(b^2+6b) +16$

$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$

$=(a-5)^2-25-(b+3)^2+9+16$

$=(a-5)^2-(b+3)^2$

5 0

3 years ago

Plz answer DDDDDDDDDDDDDDDDDD! using the line plot

masya89 [10]

Answer:

a. 6

b. 9

c. 4

Step-by-step explanation:

Range = greatest - smallest

Range = 85 - 79

Range = 6

b > 81

82, 83, 84...

3 82s

4 83s

2 85s

3 + 4 + 2 = 9

b = 83

4 83s

6 0

3 years ago