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3 years ago

6

Maryann has a hexagonal deck the needs to be painted. the apothems length is 7 feet and one side is 8 feet. what is the square f

ootage of her deck?

1 answer:

mina [271]3 years ago

5 0

A regular hexagon can be split into 6 congruent triangles

The area of one triangle = 1/2 * 8 * 7 = 28 ft^2

Area of the deck 6*28 = 168 ft^2 answer

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A person's blood glucose level and diabetes are closely related. Let x be a random variable measured in milligrams of glucose pe

soldier1979 [14.2K]

Using the normal distribution, it is found that:

a) 0.8599 = 85.99% probability that x is more than 60.

b) 0.1788 = 17.88% probability that x is less than 110.

c) 0.6811 = 68.11% probability that x is between 60 and 110.

d) 0.0643 = 6.43% probability that x is greater than 125.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

The mean is of 87, thus $\mu = 87$ .
The standard deviation is of 25, thus $\sigma = 25$ .

Item a:

This probability is <u>1 subtracted by the p-value of Z when X = 60</u>, thus:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{60 - 87}{25}$

$Z = -1.08$

$Z = -1.08$ has a p-value of 0.1401.

1 - 0.1401 = 0.8599

0.8599 = 85.99% probability that x is more than 60.

Item b:

This probability is the <u>p-value of Z when X = 110</u>, thus:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{110 - 87}{25}$

$Z = 0.92$

$Z = 0.92$ has a p-value of 0.8212.

1 - 0.8212 = 0.1788.

0.1788 = 17.88% probability that x is less than 110.

Item c:

This probability is the <u>p-value of Z when X = 110 subtracted by the p-value of Z when X = 60</u>.

From the previous two items, 0.8212 - 0.1401 = 0.6811.

0.6811 = 68.11% probability that x is between 60 and 110.

Item d:

This probability is <u>1 subtracted by the p-value of Z when X = 125</u>, thus:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{125 - 87}{25}$

$Z = 1.52$

$Z = 1.52$ has a p-value of 0.9357.

1 - 0.9357 = 0.0643.

0.0643 = 6.43% probability that x is greater than 125.

A similar problem is given at brainly.com/question/24863330

7 0

3 years ago

For every 11 litres of petrol a car can run for 50 km.

algol [13]

Answer: 50.2 liters

Step-by-step explanation:

11 liters = 50km

Z liters = 228km

To get the value of Z, cross multiply

228 x 11 = Z x 50

2508 = 50z

Divide both sides by 50

2508/50 = 50z/50

50.16 = z

50.16 has two decimal places, so convert to 1 decimal place by approximation

50.16 = 50.2

Thus, 50.2 liters will be enough for 228km

6 0

3 years ago

Read 2 more answers

Y-1.6=8.76 what is y

Verizon [17]

Answer:

y = 10.36

Step-by-step explanation:

y - 1.6 = 8.76

add 1.6 to both sides

y - 1.6 + 1.6 = 8.76 + 1.6

y = 10.36

8 0

3 years ago

Read 2 more answers

PLEASE HELP I WILL GOVE BRAINIEST

Elza [17]

Answer: the answer is x<-4 so the correct answer choice would be D

Step-by-step explanation: Hope this helps :)

7 0

3 years ago

Read 2 more answers

A hospital’s financial reimbursement payor mix indicates 35% of the patients have Medicare and 15% have Medicaid. Of those who h

Damm [24]

Using conditional probability, it is found that there is a 0.035 = 3.5% probability that a hospital patient has both Medicare and Medicaid.

<h3>What is Conditional Probability?</h3>

<em>Conditional probability</em> is the <u>probability of one event happening, considering a previous event</u>. The formula is:

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this problem, the events are:

Event A: Patient has Medicare.

Event B: Patient has Medicaid.

For the probabilities, we have that:

35% of the patients have Medicare, hence $P(A) = 0.35$ .

Of those who have Medicare, there is a 10% chance they also have Medicaid, hence $P(B|A) = 0.1$ .

Then, applying the <em>conditional </em>probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

$0.1 = \frac{P(A \cap B)}{0.35}$

$P(A \cap B) = 0.35(0.1)$

$P(A \cap B) = 0.035$

0.035 = 3.5% probability that a hospital patient has both Medicare and Medicaid.

You can learn more about conditional probability at brainly.com/question/14398287

4 0

3 years ago