The expression as a sum or difference of logarithm is log(x^3) + log(√x + 1) - 2log(x - 2)
<h3>How to write the
expression as a sum or difference of
logarithm?</h3>
The expression is given as:
log [x^3 square root x 1/(x-2)^2
Rewrite properly as:
log [x^3 √x + 1/(x-2)^2]
Express the above expression as products and quotients
log [x^3 * √x + 1/(x-2)^2]
Apply the product and quotient of logarithm
log(x^3) + log(√x + 1) - log(x - 2)^2
Rewrite as:
log(x^3) + log(√x + 1) - 2log(x - 2)
Hence, the expression as a sum or difference of logarithm is log(x^3) + log(√x + 1) - 2log(x - 2)
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Your answer is C.
3(1)2-2(2)+1=3
3=3
Hope i helped!
The answer would be 60, if you add 13,15, and 12 up you get 40. Those numbers would be considered 2/3 of all the marbles. Divide 40 by 2 to get how many marbles is 1/3. You would get 20 being a third if the marbles. Add that to the original 40 and you’ll get a total of 60.
Answer:
34
Step-by-step explanation:
The average rate of change of f(x) in the closed interval [ a, b ] is
Here [ a, b ] = [ 1, 6 ]
f(b) = f(6) = 6³ - 9(6) = 216 - 54 = 162
f(a) = f(1) = 1³ - 9(1) = 1 - 9 = - 8, thus
average rate of change = 
= 
= 34
10. √7=irrational numbers
11.
15x - 20
------------ = 15x-4
5
