Answer:
Step-by-step explanation:
Charges up to 20 passengers = $540 per person per day
Total charges = 540 × 20 = $10800
If x passengers above 20 sign up for the cruise then total number of passengers = (20 + x)
Total revenue = $(20+x)
But each fare is reduced by $7 for additional passenger above 20 then revenue generated R(x) = 540(20+x) - 7x
R(x) = 10800 + 540x - 7x
R(x) = 10800 + 533x
a). Revenue per day realized R = 10800 + 533x
b). R(48) = 10800 + 48×533
= $36,384
C). R(78) = 10800 + 78×543
= $53,154
Answer:
please write complete question
K= 100
You use distributive property
<span>
Step 1: </span><span>−(−k)−1(−86)+10=−4
Step 2: </span><span>k−1(−86)+10=−4
Step 3: </span><span>k+86+10=−4
Step 4: </span><span>k+96=−4
Step 5: </span><span>k=−96−4
Step 6: </span><span>Subtract </span>4<span> from </span><span>−96</span><span> to get </span><span><span><span>−100</span>.</span></span>
Inequality is 6t ≤ 44 and Jim can rent a boat for 7.33 hrs or less
<u>
Solution:</u>
Given that
Maximum amount Jim can spend to rent a boat = $34
Rental cost of boat for 1 hour = $6
Also Jim has a discount coupon for $8 off.
Need to determine possible number of hours Jim could rent a boat.
Let’s assume possible number of hours Jim could rent a boat be represented by variable "t"
Cost of renting boat for 1 hour = 6
So Cost of renting a boat for t hours = t x renting boat for 1 hour = t x 6 = 6t
Also Maximum amount Jim can spend to rent a boat = $34
As Jim has a discount coupon for $8 off, so Total amount Jim can spend to rent a boat = $ 34 + $ 8 = $ 44
So cost of renting a boat for t hours must be less that of equal to Total amount Jim can spend to rent a boat
=> 6t ≤ 44
On solving above equality for "t" we get ,

Hence inequality is 6t ≤ 44 and Jim can rent a boat for 7.33 hrs or less.