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Alinara [238K]
3 years ago
10

Tim invest $5,000 in an account with a bank that offers an annual interest rate of 5%, compounded quarterly. Write the function

that models the growth of a deposit of $5,000.
A(t)= __(__+(__\__)) ^__t
Mathematics
1 answer:
Marina86 [1]3 years ago
3 0

9514 1404 393

Answer:

  A(t) = 5000(1 +.05/4)^(4t)

Step-by-step explanation:

The compound interest formula is ...

  A = P(1 +r/n)^(nt)

where principal P earns interest at annual rate r compounded n times per year for t years. The problem statement tells you P=5000, r=0.05, n=4. Putting these values into the formula gives ...

  A(t) = 5000(1 +0.05/4)^(4t)

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HELP
Reptile [31]

Answer:

The time it takes for the cannonball to hit the ground is 6.49 seconds.

Step-by-step explanation:

You know that the height of the cannonball above the ground, h, in meters, in time, t, in seconds, is found by the function h(t) = -4.9t² + 30.5t + 8.4. You want to calculate the time it takes for the cannonball to hit the ground, that is, the time it takes for the bullet to reach zero height. So, being h(t) = 0 you have:

0 = -4.9t² + 30.5t + 8.4

To solve a quadratic function 0=a*x² + b*x +c, the expression is applied:

\frac{-b+-\sqrt{b^{2} -4*a*c} }{2*a}

In this case, being a = -4.9, b =30.5 and c =8.4  you have:

\frac{-30.5+-\sqrt{30.5^{2} -4*(-4.9)*8.4} }{2*(-4.9)}

Solving you get:

t1= -0.26 seconds and t2=6.49 seconds

Since time does not have a negative value, then <u><em>the time it takes for the cannonball to hit the ground is 6.49 seconds.</em></u>

3 0
3 years ago
Point p(a,b) is in the first quadrant on the graph of the line x+y=4. A triangular region is shown on the diagram. What is the m
Gala2k [10]

Answer:

The maximum area of the triangular region is 2 square units

Step-by-step explanation:

we know that

The area of the triangular region is equal to

A=\frac{1}{2}(x)(y) -----> equation A

where

x is the x-coordinate of point P

y is the y-coordinate of point P

we have

The equation of the graph of the line is

x+y=4

y=-x+4 -----> equation B

substitute equation B in equation A

A=\frac{1}{2}(x)(-x+4)

A=-\frac{1}{2}x^2+2x

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The y-coordinate of the vertex represent the maximum area of the triangular region

Find the vertex

Convert the quadratic equation in vertex form

Factor -1/2

A=-\frac{1}{2}(x^2-4x)

Complete the square

A=-\frac{1}{2}(x^2-4x+4)+2

Rewrite as perfect squares

A=-\frac{1}{2}(x-2)^2+2

The vertex is the point (2,2)

so

The maximum area is the y-coordinate of the vertex

The maximum area of the triangular region is 2 square units

Find the coordinates of point P for the maximum area

x=2 (x-coordinate of the vertex)

Find the y-coordinate of point P

substitute in equation B

y=-2+4=2

The coordinates of point P for the maximum area is P(2,2)

3 0
4 years ago
For f(x) = 24-2x, find F(3) and F(5)
love history [14]

Answer:

Step-by-step explanation:

C

4 0
3 years ago
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What are some whole numbers that are greater than 15 but less than 26?
Elza [17]

16, 17, 18, 19, 20, 21, 22, 23, 24, and 25

3 0
4 years ago
PLEASE HELP!!!!!!! WILL GIVE 50 POINTS!!!!!
Ivahew [28]

Answer:

10 units

Step-by-step explanation:

I hope this helps!

7 0
3 years ago
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