Answer:
A regular 12-oz beer is about 5% alcohol. This works out to about 14.03 grams of alcohol per beer. If the driver drank two beers, how many grams of alcohol did he consume? <u>28.06 grams</u>
The driver weighs about 160 lbs. What is his body weight in kg? What is his body volume in mL? (1 lb = 0.45 kg) (1 kg = 1000 mL) <u>72.57 kg/72,560 mL</u>
For most males, 68 percent of the body is water. What is the volume of water in the driver’s body in mL? <u>49,350 mL</u>
Use the above information to calculate BAC. <u>0.0569%</u>
The measured BAC was 0.12%. Was the driver telling the truth about how much he drank? Calculate the difference between the two BAC percentages. <u>No. 0.0569% is different.</u>
If the driver had really consumed only two beers, would he have been arrested for DUI? Explain. <u>The driver would not have been arrested if he only had two beers. He more or less had more than two beers in his car when the police checked his car.</u>
Step-by-step explanation:
the underlined areas are your answers.
Answer:
looks like A, first answer, is correct when using n such that it names what value of the sequence to use like a1 = 4 and so on.
Step-by-step explanation:
Step-by-step explanation:
radius of sphere, rs
radius of cylinder, rc
height of cylinder, h
given: h = rs = rc =r..eq1
volume of cylinder, vc = 27pi ft...eq2
volume of cylinder, vc = pi × rc^2 × h...eq3
volume of sphere, vs = 4/3(pi×rs^3)...eq4
subst for h & rs from eqn 1 in eqn 3...
vc = pi x r^2 x r= pi x r^3...eqn 5
subst for vc from eqn 2 in eqn 5...
=> 27 pi ft = pi x r^3
=> 27 = r^3
=> r = 3ft...eqn 6
subst for rs from eqn 1 in eqn 4
vs = 4/3 (pi x r^3)...eqn7
subst for pi x r^3 from eqn 5 in eqn 7
vs = 4/3 vc = 4/3 (27pi ft) = 36 pi ft
The area of a sector of a circles is calculated by the equation A = πr^2 (theta/360). From the data of the sector, we determine the radius of the circle. THen, we can calculate for the area of the circle.
16.4π = πr^2 (72/360)
r = 9.06
Area of circle = πr^2
Area of circle = π(9.06)^2
Area of circle = 82π
Answer:
volume of the sphere
=4/3π × r³
=4/3π × 3 × 3 × 3
=4/3π × 27
=36π ( <em>c</em><em> </em><em>)</em>
