Answer:
A or B
Explanation:
hope this helps please tell me if I’m wrong
Answer:
Any time a body is in an environment that is colder than 98.6 F (37 C), heat is lost. And since the heat loss in water is 25 times faster than to air, this may occur fairly quickly.
Explanation:
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Answer:
WILD TYPE= 425;
TAN-BARE= 425;
TAN= 75;
BARE= 75
Explanation:
Fifteen map units apart implies that 15% of the offspring are products of recombination.
Out of 1000 offsprings, therefore 15% of 1000= 0.15 × 1000=150
150 offsprings are products of recombination.
100-15 =85%
Therefore, 85% of the offspring are parental.
So, if tan-bodied, ware-winged female was mated with wild-type male resulting in F1 phenotypically wild-type females were mated to tan-bodied, bare-winged males.
The expected number of offsprings that are tanned but have normal wings would be:
Wild type= 50% of 850
0.50 × 850 = 425
Tan-bare= 50% of 850
0.50 × 850 = 425
tan= 50% of 150
0.50×150= 75
Bare= 50% of 150
0.50×150=75
