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3 years ago

Solve for x in the figure. 78° [(5x-210

Mathematics

2 answers:

Sergeeva-Olga [200]3 years ago

4 0

Answer:

$78 = (5x - 2) \\ \\ 78 = 5x - 2 \\ \\ 78 + 2 = 5x \\ \\ 80 = 5x \\ \\ x = \frac{80}{5} \\ \\ x = 16$

it's was vertical angel they are equal ( = ) each other

it's was helpful to you

Elza [17]3 years ago

3 0

<h2>Solution:-</h2>

$\\ \mapsto78 = (5x - 2)$

$\\ \mapsto78 = 5x - 2$

$\\ \mapsto78 + 2 = 5x$

$\\ \mapsto80 = 5x$

$\\ \mapsto \frac{80}{5} = x$

$\\ \mapsto16 = x$

$\\ \mapsto \: x = 16$

<h2>Answer:-</h2>

[Hence, the value of x is 16.]

<h3>Hope it's helpful !</h3>

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The area of rectangular is 64m the length of the pool is 12 m less that the width .The situation can be represented by the equat

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Answer:

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Step-by-step explanation:

The area of rectangular is 64m² the length of the pool is 12 m less that the width . The situation can be represented by the equation x

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What multiplies to 16 and adds to negative 12

Romashka-Z-Leto [24]

Factor 16 and see the - factor pairs and add them, see which add to -12
-1-16=-17 nope
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hmm

we will solve with math
xy=16
x+y=-12
minus x both sides
y=-12-x
sub for y in other equation
x(-12-x)=16
-12x-x^2=16
add 12x+x^2 both sides
0=x^2+12x+16
use quadratic formula
if you have
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$

0=x^2+12x+16
a=1
b=12
c=16

x= $\frac{-12+/- \sqrt{12^{2}-4(1)(16) }}{2(1)}$
x= $\frac{-12+/- \sqrt{144-64 }}{2}$
x= $\frac{-12+/- \sqrt{80}}{2}$
x= $\frac{-12+/- 4\sqrt{5}}{2}$
x= $\frac{-6+/- 2\sqrt{5}$
x= $\frac{-6+ 2\sqrt{5}$ or $\frac{-6- 2\sqrt{5}$

aprox
x=-1.52786 or -10.4721

those are the numbers

the numbes are -1.52786 or -10.4721

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nikitadnepr [17]

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